Ans: a = 2.50 m/s^2
Explanation:
First convert the mass in its standard unit i.e. kilogram(kg):
2250 lbs = 1020.583kg
Next use Newton's Second law:
F = ma
Where F = 2552N
m = 1020.583kg
=> a = (2552/1020.583)
a = 2.50 m/s^2
We can use the law of conservation of energy to solve the problem.
The total mechanical energy of the system at any moment of the motion is:

where U is the potential energy and K the kinetic energy.
At the beginning of the motion, the ball starts from the ground so its altitude is h=0 and therefore its potential energy U is zero. So, the mechanical energy is just kinetic energy:

When the ball reaches the maximum altitude of its flight, it starts to go down again, so its speed at that moment is zero: v=0. So, its kinetic energy at the top is zero. So the total mechanical energy is just potential energy:

But the mechanical energy must be conserved, Ef=Ei, so we have

and so, the potential energy at the top of the flight is
Answer:
31.905 ft/s²
Explanation:
Given that
Mass of the pilot, m = 120 lb
Weight of the pilot, w = 119 lbf
Acceleration due to gravity, g = 32.05 ft/s²
Local acceleration of gravity of found by using the relation
Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)
119 = 120 * a/32. 174
119 * 32.174 = 120a
a = 3828.706 / 120
a = 31.905 ft/s²
Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²
Answer:
0.28802
2.57162 W
14.28 W
53.55 W
6.07142 W
Explanation:
R = 280Ω
L = 100 mH
C = 0.800 μF
V = 50 V
ω = 10500rad/s
For RLC circuit impedance is given by

Power factor is given by

The power factor is 0.28802
The average power to the circuit is given by

The average power to the circuit is 2.57162 W
Power to resistor

Power to resistor is 14.28 W
Power to inductor

Power to the inductor is 53.55 W
Power to the capacitor

The power to the capacitor is 6.07142 W
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