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3 years ago

5

Calcula la fuerza magnética de una carga que se desplaza hacia la derecha con una velocidad de 5 X 10 a la 6 metros sobre segund

o. Que forma un campo magnético de 0.8 Teslas. Recuerda que la carga de un electrón es de 1.602 X 10 a la menos 19 [Coulombs]

1 answer:

Diano4ka-milaya [45]3 years ago

3 0

Answer:

La fuerza magnética del electrón es 6.41x10⁻¹³ N.

Explanation:

Podemos encontrar la fuerza magnética (F) usando la ley de Lorentz:

$F = qv\times B$

En donde:

q: es la carga del electrón = 1.602x10⁻¹⁹ C

v: es la velocidad del electrón = 5x10⁶ m/s

B: es el campo magnético = 0.8 T

$F = qv\times B = 1.602 \cdot 10^{-19} C*5\cdot 10^{6} m/s*0.8 T = 6.41 \cdot 10^{-13} N$

Por lo tanto, la fuerza magnética del electrón es 6.41x10⁻¹³ N.

Espero que te sea de utilidad!

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The atom becomes a positively charged ion.

Explanation:

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3 years ago

n deep space, sphere A of mass 47 kg is located at the origin of an x axis and sphere B of mass 110 kg is located on the axis at

Volgvan

Answer:

a)-1.014x $10^{-7$ J

b)3.296 x $10^{-7$ J

Explanation:

For Sphere A:

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As sphere starts from rest and sphere A is fixed at its place, therefore $K_{i$ is zero

$U_{i$ = $K_{f$ + $U_{f$

The final potential energy is

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$K_{f$ = 3.296 x $10^{-7$ J

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Answer:

The answer is " $60.74^{\circ}$ ".

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Cavity and benzene should be extended in equal quantities.

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Answer:

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We here know that as $sin\theta$ as w are constant, then

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