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Anon25 [30]
2 years ago
5

Calcula la fuerza magnética de una carga que se desplaza hacia la derecha con una velocidad de 5 X 10 a la 6 metros sobre segund

o. Que forma un campo magnético de 0.8 Teslas. Recuerda que la carga de un electrón es de 1.602 X 10 a la menos 19 [Coulombs]
Physics
1 answer:
Diano4ka-milaya [45]2 years ago
3 0

Answer:

La fuerza magnética del electrón es 6.41x10⁻¹³ N.

Explanation:

Podemos encontrar la fuerza magnética (F) usando la ley de Lorentz:

F = qv\times B

En donde:

q: es la carga del electrón = 1.602x10⁻¹⁹ C

v: es la velocidad del electrón = 5x10⁶ m/s

B: es el campo magnético = 0.8 T

F = qv\times B = 1.602 \cdot 10^{-19} C*5\cdot 10^{6} m/s*0.8 T = 6.41 \cdot 10^{-13} N                                

Por lo tanto, la fuerza magnética del electrón es 6.41x10⁻¹³ N.

Espero que te sea de utilidad!  

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Answer:15,883.63 KJ

Explanation:

Given

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and we know COP of refrigerator is given by

COP=\frac{T_L}{T_H-T_L}=\frac{Desired\ effect}{Work}

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DanielleElmas [232]

Answer:

Electronegativity is a chemical property at the top of the periodic table

Explanation:

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Answer:

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2gh = Vf² - Vi²

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g = acceleration due to gravity on the surface of earth = - 9.8 m/s² (negative sign due to upward motion)

h = height of pellet = 100 m

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(2)(-9.8 m/s²)(100 m) = (0 m/s)² - Vi²

Vi = √(1960 m²/s²)

Vi = 44.27 m/s

Now, we use this equation at the surface of moon with same initial velocity:

2g'h' = Vf² - Vi²

where,

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