1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Effectus [21]
3 years ago
9

A physics experiment is done in which three masses are used to balance a bar on a fulcrum. Two masses (21 kg and 12 kg) are plac

ed on one side of the fulcrum, 12 cm and 21 cm away, respectively. Where must the third mass (18 kg) be placed in order to make the bar balance?
Physics
1 answer:
Butoxors [25]3 years ago
8 0
You have to balance the torque in order to make the bar balance
torque on the 21 kg mass is equal to = 21*10*0.12 = 25.2 NM
torque on the 12 kg mass is equal to = 12*10*0.21=
25.2 NM
THUS total comes to 50.4 NM
to to balance the torque
50.4/180 = 0.28 that's 28 cm from the centre to the opposite of the both masses
You might be interested in
Find the currents flowing in the circuit in the figure below. (Assume the resistances are
Nitella [24]

By Kirchoff's law in left side loop

E_1 + E_2 = {r_1 + R_1 + R_4)I_1 + (R_2 + r_2) I_3

similarly kirchoff's law in right side loop

E_3 - E_4 - E_2 = (r_3 + r_4 + R_3)I_2 - (R_2 + r_2)I_3

also by junction law we know that

I_1 = I_2 + I_3

now by plug in all values we have

18 + 3 = (0.5 + 8 + 15)I_1 + (10 + 0.25)I_3

21 = 23.5I_1 + 10.25I_3

12 - 24 - 3 = (0.75 + 0.25 + 12)I_2 - (10+ 0.25)I_3

-15 = 13I_2 - 10.25I_3

So by solving above equations we have

I_1 = 0.492 A

I_2 = -0.428 A

I_3 = 0.920 A

6 0
4 years ago
Now, using your mass (in kg), and the figures for g (in the table below), you can calculate your weight on other planets.
Licemer1 [7]

Answer:

1) Weight on Mercury

F =W=mg=68.11 \times 3.61 m.s^{-2}

Explanation:

do the same to the rest and use your calculator to find the weight in N.

3 0
3 years ago
A person who weighs 69kg rides with an acceleration of +1.45 m/s2. What is the force exerted by the legs on the person's upper b
trapecia [35]

Answer:

The force exerted by the legs on the person's upper body 32.106 N.

Given:

Mass = 69 kg

Acceleration = 1.45 \frac{m}{s^{2} }

To find:

Force exerted by legs on the person's upper body = ?

Formula used:

Force = mass × acceleration

Solution:

Mass of legs = \frac{32}{100} mass of body

Mass of legs = 22.08 kg

According to Newton's second law of motion,

Force = mass × acceleration

Force = 22.08 × 1.45

Force = 32.106 N

The force exerted by the legs on the person's upper body 32.106 N.

4 0
4 years ago
A hot air balloon is ascending straight up at a constant speed of 8.40 m/s. When the balloon is 14.0 m above the ground, a gun f
MakcuM [25]

Answer:

The objects have the same altitude at the same time in the heights 22.4m and 36.6m.

Explanation:

The equation of the position y of the hot air balloon with respect to time is:

y=y_0+v_{0B}t

And the equation of the position y of the pellet with respect to time is:

y=v_{0P}t-\frac{1}{2} gt^{2}

As the altitude of the two objects must be equal, we can match these equations, so:

y_{0B}+v_{0B}t=v_{0P}t-\frac{1}{2} gt^{2} \\\\\frac{1}{2} gt^{2}+(v_{0B}-v_{0P})t+y_{0B}=0\\\\4.9\frac{m}{s^{2}}t^{2} -18.6\frac{m}{s} t+14.0m=0

Solving this equation for t, we obtain:

t=\frac{18.6\frac{m}{s} \±\sqrt{345.9\frac{m^{2}}{s^{2}}-4(4.9\frac{m}{s^{2}})(14.0m)}}{9.8\frac{m}{s^{2}}}=\frac{18.6\frac{m}{s}\±8.4\frac{m}{s}}{9.8\frac{m}{s^{2}}} \\\\\implies \left \{ {{t_1=1.0s} \atop {t_2=2.7s}} \right.

Now, using the equation of the position of the balloon (we can use the other either, but the first one is easier) we can obtain the height of the places where the two objects have the same altitude at the same time:

y_1=14.0m+8.40\frac{m}{s} (1.0s)=22.4m\\\\y_2=14.0m+8.4\frac{m}{s}(2.7s)=36.6m

In words, the hot air balloon and the pellet have the same altitude at the same time in the heights 22.4m and 36.6m.

7 0
3 years ago
Why concave lens is called diverging lens​
dangina [55]

When a parallel beam of light passes through a convex lens, the rays become farther from one another when the come out. This process of rays is called ''to diverge''. The concave lens makes rays of light diverge, so it is called diverging lens.

6 0
3 years ago
Other questions:
  • What symbol is used when representing momentum in equations?
    13·1 answer
  • If a truck travels 100 miles in 2 hours, what is its speed? (Hint: Do not forget to write the unit).
    14·1 answer
  • Um objeto de 200 kg é acelerado a 4 m/s2 sob ação de uma força F. Determine a distância deslocada pelo objeto sob ação dessa for
    10·1 answer
  • PLEASE HURRY!
    6·2 answers
  • Is gravity air resistance?
    15·1 answer
  • Which of these is an effect of space travel?
    12·1 answer
  • A man walking on a tightrope carries a long a pole which has heavy items attached to the two ends. If he were to walk the tight-
    6·1 answer
  • Suppose a spring has a relaxed length of 28.3 cm. The simulation refers to this as the natural length. This is the length of the
    15·1 answer
  • Un hombre de pie puede ejercer la misma fuerza con sus piernas tanto en la tierra como en la luna. Sabemos que la masa del hombr
    10·1 answer
  • A 16 Ω resistor and a 6 Ω resistor are connected in series to an ideal 6 V battery.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!