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3 years ago

Does this represent a function?

Mathematics

1 answer:

Anettt [7]3 years ago

3 0

Answer:

No.

Step-by-step explanation:

A graph must pass the Vertical Line Test in order to be a function. Since this graph doesn't pass the test, it is not a function.

However, this graph is a conic, specifically a hyperbola.

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Please solve this question <br> (2x3)x2+5x2

oksano4ka [1.4K]

(2×3)×2+5×2=22

2×3=6

6×2+5×2

12+5×2

12+10

22

5 0

3 years ago

An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s

maks197457 [2]

Answer:

$W_s \approx5.3$

Step-by-step explanation:

From the question we are told that

Height $H=3.5ft$

Weight $W= 6ft$

Depth $D=0.95ft$

Generally the equation for ellipses is given as

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

Where

$b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\$

$\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1$

Generally to find y in the equation $\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

$y=-b+d$

$y=-1.75+0.95$

$y=-0.8$

Therefore

$\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1$

$\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}$

$\frac{x^2}{3^2} =1-0.2089795918$

$X^2 =3^2(1-0.2089795918)$

$X^2 =7.119183674$

$X =\sqrt{7.119183674}$

$X =2.66817984$

Therefore the width of the given stream is

$W_s=2.66817984*2$

$W_s=5.33635968$

$W_s \approx5.3$

3 0

3 years ago

al receives $25 weekly allowance. he also babysits his two younger siblings on weekends and is paid $9 per hour. al's friend, Ma

Harlamova29_29 [7]

To answer this question you would set this up as an equation with all the information about Al on one side being equal to all the information for Matthew on the other side. This is what it would look like: $25 + $9h= $14h. h represents the number of hours they work. It they each worked 5 hours a week, they would make the same amount of money. I determined this by solving the equation for h. I subtracted 9h on both sides leaving you with $25=5h. H would equal 5 hours.

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3 years ago

Yvonne is interested in testing the effectiveness of a new flea medication on dogs, so she divided some dogs with fleas into two

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