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3 years ago

12

How did the electron change the model of the atom?

1 answer:

Evgesh-ka [11]3 years ago

4 0

According to John Dalton, atoms are indivisible which means that they can not be broken down into smaller particles. However, J.J Thomson have proven the existence of electrons. The existence of sub-atomic particles disproved Dalton's theory. Thomson conducted his experiment using a cathode ray-tube.

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A jumbo jet of mass 100,000 kg during takeoff experience a thrust for each of its four engines of 50,000 N. producing an acceler

PtichkaEL [24]

Answer:

F=MA

5OOOO=100000×A

50000/100000=A

A=5/10 M/ S SQ

A=0.5 M/S SQ.

8 0

4 years ago

As the distance between 2 objects increases, what happens to gravitational force?

ExtremeBDS [4]

Answer:

the force decreases

Explanation:

Gravitational force is depending on it's mass and the distance between two object

The attachment shows us to understand relationship of it's

F ∝ 1/ (r)2

there for gravitational force is inversely proportional to it's distance . when distance between two object is increased, Then force will be decreased

3 0

3 years ago

brainliest. Which layer of the atmosphere has the air we breathe? Mesosphere Stratosphere Thermosphere Troposphere

Nat2105 [25]

Answer:

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4 years ago

Read 2 more answers

A platinum resistance thermometer has a resistance of 11.50 ohms at 0 oC and 17.35 ohms at 100 oC. Assuming that the resistance

STatiana [176]

Answer:

$34.2^{\circ}C$

Explanation:

The resistance increases linearly with the temperature - so we can write:

$\Delta R = k \Delta T$

where

$\Delta R$ is the change in resistance

k is the coefficient of proportionality

$\Delta T$ is the variation of temperature

In the first part of the problem, we have

$\Delta R = 17.35 - 11.50 =5.85\Omega$

$\Delta T = 100 -0 = 100^{\circ}C$

So the coefficient of proportionality is

$k=\frac{\Delta R}{\Delta T}=\frac{5.85}{100}=0.0585 \Omega ^{\circ}C^{-1}$

When the resistance is $R=13.50\Omega$ , the change in resistance with respect to the resistance at zero degrees is

$\Delta R' = 13.50-11.50 = 2.00 \Omega$

So we can find the change in temperature as:

$\Delta T' = \frac{\Delta R}{k}=\frac{2.00}{0.0585}=34.2^{\circ}$

So the new temperature is

$T_f = T_0 + \Delta T' = 0+34.2 = 34.2^{\circ}C$

4 0

3 years ago

Potential energy increases with the greater height mass of an object.True or False

guapka [62]

Answer:

Potential energy increases with the greater height mass of an object.

<h2><u><em>TRUE</em></u></h2>

5 0

4 years ago