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svlad2 [7]
3 years ago
12

How did the electron change the model of the atom?

Physics
1 answer:
Evgesh-ka [11]3 years ago
4 0
According to John Dalton, atoms are indivisible which means that they can not be broken down into smaller particles. However, J.J Thomson have proven the existence of electrons. The existence of sub-atomic particles disproved Dalton's theory. Thomson conducted his experiment using a cathode ray-tube.
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The balloon's behavior results from a change at the electron level. What do you think might have happened while rubbing the ball
Mariulka [41]

Answer:

Explanation:

opposite charges attract each other, while rubbing the objects together they developed opposite charges which caused them to drift together

6 0
4 years ago
Which statement best describes how light waves travel in a uniform medium?
Zanzabum
The statement which best describes how light waves travel in an uniform medium is in straight lines. The correct answer will be A. 
5 0
3 years ago
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A small ball of charge Q and mass m has a velocity v at infinity. It collides head-on with a ball of the same charge and mass wh
Hatshy [7]

Answer:

Explanation:

Kinetic energy of ball in motion = 1/2 m v² . Potential energy = 0

Let the minimum distance between the balls be d  on collision.

Electric potential energy at that time= k Q²/d , Here kinetic energy is converted into potential energy . So

1/2 m v² = kQ²/d

d =2 k Q² / mv²,= 18 x 10⁹ x Q²/ m v².

8 0
4 years ago
Where is nitrogen found?
iren2701 [21]
It found on Earth atmosphere.
3 0
3 years ago
1-D Kinematics, Constant Acceleration After falling a distance of 45.0 m from the top of a building, a box is landing on the top
Mrrafil [7]

Answer:

Explanation:

Given

Object fall from a height of s=45\ m

Considering initial velocity to be zero i.e. u=0

using

v^2-u^2=2as  

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

v^2-0=2(9.8)\cdot 45

v=29.69\ m/s\approx 29.7\ m/s

(b)Average acceleration

After falling 45 m, object strike the car and comes to rest after covering a distance of 0.5 m

again using

v'^2-u'^2=2as'

here final velocity will be zero i.e.v'=0

initial velocity u'=v

0-(29.7)^2=2\cdot a\cdot 0.5

a=-882.09\ m/s^2

(c)time taken by it to stop

v'=u'+a't

0=29.7-882.09\cdot t

t=0.034\ s

5 0
3 years ago
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