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Inessa [10]
3 years ago
6

Where is nitrogen found?

Physics
1 answer:
iren2701 [21]3 years ago
3 0
It found on Earth atmosphere.
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A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the gr
k0ka [10]

This question is incomplete, the complete question is;

A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the green part of the visible spectrum (λ=520nm) is I, find the intensity (in terms of I) of scattered light

a) In the middle of the red part of the spectrum (λ= 665 nm)

b) In the middle of the violet part of the spectrum (λ = 420 nm)

Answer:

a) the intensity of scattered light ( in terms of I ) In the middle of the red part of the spectrum is 0.3739I

b) the intensity of scattered light ( in terms of I ) In the middle of the violet part of the spectrum is 2.3497I  

Explanation:

Given the data in the question,

the visible spectrum (λ=520nm) = I

we know that; intensity of scattered light is proportional to 1 / λ⁴  

I ∝ ( 1 / λ⁴ )

so

a)

I_R / I = ( λ / λ_R )⁴

As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ_R is 665 nm

we substitute

I_R / I = ( 520 / 665 )⁴

I_R / I = ( 0.781954887 )⁴

I_R / I = 0.3739

I_R  =  0.3739I  { in terms of I  }

Therefore, the intensity of scattered light ( in terms of I ) In the middle of the red part of the spectrum is 0.3739I

b)

I_V / I = ( λ / λ_V )⁴

As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ_R is 420 nm

we substitute

I_V / I = ( 520 / 420 )⁴

I_V / I = ( 1.238095 )⁴

I_V / I = 2.3497

I_V = 2.3497I  { in terms of I  }

Therefore, the intensity of scattered light ( in terms of I ) In the middle of the violet part of the spectrum is 2.3497I  

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