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Hatshy [7]
3 years ago
8

A small ball of charge Q and mass m has a velocity v at infinity. It collides head-on with a ball of the same charge and mass wh

ich is initially at rest. What is the minimal distance between the charges during the collision?
Physics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

Explanation:

Kinetic energy of ball in motion = 1/2 m v² . Potential energy = 0

Let the minimum distance between the balls be d  on collision.

Electric potential energy at that time= k Q²/d , Here kinetic energy is converted into potential energy . So

1/2 m v² = kQ²/d

d =2 k Q² / mv²,= 18 x 10⁹ x Q²/ m v².

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4. In which of the following circuits will the bulb glow?
Zanzabum

Answer:

I believe is C.

Explanation:

its quite obvious:)

4 0
2 years ago
Name three forces involved in brushing your teeth.
Viefleur [7K]
Three forces involved in brushing your teeth are first push, then pull, then push.
3 0
3 years ago
A 17-car train standing on the siding is started in motion by the train’s engine. 9 cm slack is between each of the cars, which
BaLLatris [955]

Answer:

4 seconds

Explanation:

There are links between cars, they are in between

1-2, 2-3, 3-4, 4-5, 5-6, 6-7, 7-8, 8-9, 9-10, 10-11, 11-12, 12-13, 13-14, 14-15, 15-16, 16-17.

Here 1 represents the first car which is firmly attached to the engine. So, there are 16 links and each link has a slack of 9 m.

So, total slack

9×16 = 144 cm

Speed of train = 36 cm/s

\text{Time taken by the pulse}=\frac{Length}{speed}\\\Rightarrow \text{Time taken by the pulse}=\frac{144}{36}\\\Rightarrow \text{Time taken by the pulse}=4\ s

Time taken by the pulse to travel the length of train is 4 seconds.

6 0
2 years ago
Velocities of two bodies A and B are given in vectors notation as va =i+2j-3k and Vb=3i+2j-k what will be the relative velocity
ArbitrLikvidat [17]

Answer:

V_{B/A}=2i+2k

Explanation:

The relative velocity can be calculated by means of the difference between vector B minus vector A.

V_{A}=i+2j-3k\\V_{B}=3i+2j-k\\V_{B}-V_{A}=(3-1)i + (2-2)j+(-1-(-3))k\\V_{B/A}=2i+2k

5 0
3 years ago
Sam, whose mass is 75 kg , takes off across level snow on his jet-powered skis. The skis have a thrust of 160 N and a coefficien
Volgvan

Answer:

top speed = 17.25

Total height = 281.19 m

Explanation:

given data

mass = 75 kg

thrust = 160 N

coefficient of kinetic friction = 0.1

solution

we get here frictional force acting that is

frictional force = \mu *m*g   .............1

frictional force = 0.1 × 75 × 9.8

frictional force = 73.5 N

and

Net force acting will be F = 160 - 73.5  N

F = 86.5 N

so

Acceleration in the First 15 second  will be

F = ma .........2

86.5 = 75 × a

a = 1.15 m/s²

and

now After 15 second the velocity will be  as

v = u + at   ..........3

here u is 0

so v will be

V = 1.15 × 15

v = 17.25

and

now we get travels distance S  in 15 s

s = u × t + 0.5 × a × t²  

here u is 0

so distance s will be

s = 0.5 × a × t²  

s = 0.5 ×  1.15 × 15²  

s = 129.37 m

and

now  acceleration acting is

F =  \mu *m*g  

m a =  \mu *m*g

a = \mu* g

a = - 0.98

here it is negative it mean downward nature of acceleration

and

now we get distance s by this formula

V² - u² = 2 a s    

here v velocity is 0  and

u initial velocity is 17.25 m/s

put here value

0 - 17.25² = 2 × (-0.98) × s    

solve it we get

s = 151.82 m

so

Total height is

Total height = 129.37 m + 151.82 m

Total height = 281.19 m

7 0
3 years ago
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