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3241004551 [841]
3 years ago
14

a rectangle has a width of 3 units. The rectangles length is 5 times it’s width. what is the area of the rectangle?

Mathematics
2 answers:
Korvikt [17]3 years ago
7 0

Answer:

Step-by-step explanation:

45 15 x 3=45

Kazeer [188]3 years ago
3 0

Answer:

45 units²

Step-by-step explanation:

width = 3 units

length = 5×width = 5×3 = 15 units

Area = length × width

= 15 × 3 = 45 units²

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HELP PLEASEEE
djyliett [7]

Answer:

Exact circumference is 7\frac{49}{150}km

Approximate circumference is 7.33 km

Step-by-step explanation:

We are given;

  • The diameter of a circle as 2\frac{1}{3} km

We are required to determine the exact and approximate circumference of the circle.

  • We know that the circumference of the circle is given by;
  • Circumference = πD, where D is the diameter

Taking π as 3.14

Circumference=3.14 (2\frac{1}{3}km)

                          =7\frac{49}{150}km

The exact circumference of the circle is 7\frac{49}{150}km

7\frac{49}{150}km=7.327 km\\                            = 7.33 km (nearest hundredth)

Thus, the approximate circumference of the circle is 7.33 km

6 0
4 years ago
Increase £30 by 2/5?
Sergeu [11.5K]
2/5 of 30 = 12
30 + 12 = 42
£42
6 0
4 years ago
1.The table shows the results of drawing colored marbles from a bag.
Yanka [14]
1. The table shows the results of drawing colored marbles from a bag. <span>Based on theoretical probability, the best prediction for the number of times a red marble would be drawn in 1000 trials is 167. The answer is letter C.

2. </span>A spinner has ten equal sections labeled A through J. In 50 spins, the spinner stopped on the section labeled J 12% of the time. <span>The percent of times the spinner stops on J will be exactly 10%. The answer is letter C.</span>
7 0
3 years ago
The width of jays original photo is 8 inches. The length of the original photos is 10 inches. He prints a smaller version that h
aleksandrvk [35]
I'm guessing the answer is 6in.
because the original width of the photo is 8in-4in 
which is 4in.
and 8 to 10 is a difference of 2 
so add 2 to 4 
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8 0
3 years ago
A university with a high water bill is interested in estimating the mean amount of time that students spend in the shower each d
Bas_tet [7]

Answer: (4.0845,\ 6.5755)

Step-by-step explanation:

As per given , we have

n = 11

\overline{x}=5.33\\\\ s=1.33

Since population standard deviation is missing, so we use t-test.

Critical t-value for 99% confidence :

t_{\alpha/2,\ n-1}=3.106   [using two-tailed t-value table]

Confidence interval :

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}\\\\= 5.33\pm (3.1060)\dfrac{1.33}{\sqrt{11}}\\\\\approx5.33\pm1.2455\\\\=(5.33-1.2455,\ 5.33+1.2455)\\\\=(4.0845,\ 6.5755)

Hence,  99% confidence interval for the mean amount of time that students spend in the shower each day.= (4.0845,\ 6.5755)

7 0
3 years ago
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