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Veronika [31]
3 years ago
5

What is the simplified form of 45? A. 5 B. 9.5 C. 3/5 D. 5/3

Mathematics
2 answers:
DENIUS [597]3 years ago
7 0

Answer:

Since radical 45 is equal to radical 9 times radical 5, and because radical 9 is equal to 3 (since 9 is a perfect square), we can simplify radical 45 to 3 times radical 5 

leva [86]3 years ago
7 0

Answer:

the answer is 5

Step-by-step explanation:

when u simplifying its the lowest number u can go but make sure u can multiply to get the answer

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Solve for x: 2x squared-1=-9
Troyanec [42]

Answer:

x=-2

Step-by-step explanation:

-9+1=-8 so 2x squared =-8

x=-2

3 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
The power generated by an electrical circuit (in watts) as a function of its current x xx (in amperes) is modeled by P ( x ) = −
marysya [2.9K]

Given:

The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled by

P(x)=-15x(x-8)

To find:

The current which will produce the maximum power.

Solution:

We have,

P(x)=-15x(x-8)

P(x)=-15x^2+120x

Differentiate with respect to x.

P'(x)=-15(2x)+120(1)

P'(x)=-30x+120      ...(i)

To find the extreme point equate P'(x)=0.

-30x+120=0

-30x=-120

Divide both sides by -30.

x=4

Differentiate (i) with respect to x.

P'(x)=-30(1)+(0)

P'(x)=-30 (Maximum)

It means, the given function is maximum at x=4.

Therefore, the current of 4 amperes will produce the maximum power.

7 0
3 years ago
Look at this graph:
Andrew [12]

Answer:

2

Step-by-step explanation:

slope=rise/run=2/1=2

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