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Bad White [126]
3 years ago
13

Carmela saves 8% of her weekly earnings. She earned $25 last week. How

Mathematics
2 answers:
Sloan [31]3 years ago
7 0
The answer is B. $2.00
BabaBlast [244]3 years ago
3 0

Answer:

$2

Step-by-step explanation:

So, 8% is the same as 8/100 or .08. I'll be using .08 to make things more simple. Now, if she earned $25 last week and she saves 8% of it then, the equation to find how much she saved would be 25 times .08. Simply plug that into a calculator to get the answer $2.

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We need to see the expressions given

Step-by-step explanation:

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The distance from the school to Brandi's house is 1,240 meters. Leaving the school, she rides her bicycle for 60 seconds at a sp
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14,880 seconds i think
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3 years ago
Determine whether the integral from -3 to infinity 1/sqrt (5 - x) is divergent or convergent. If it is convergent, evaluate it.
BigorU [14]

It's divergent because 1/√(5 - <em>x</em>) is defined only for <em>x</em> < 5, which means the integral from 5 to infinity doesn't exist.

5 0
3 years ago
How do i solve each proportion?
natali 33 [55]
You have to cross multiply (multiply the numerator of the first by the denominator of the second and the numerator of the second by the denominator of the first).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[19]

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[21]

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8 0
3 years ago
Read 2 more answers
Please someone answer this please
gladu [14]

Option C:

\frac{3 a^{2} b^{11}}{2 } is equivalent to the given expression.

Solution:

Given expression:

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}

To find which expression is equivalent to the given expression.

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}

Using exponent rule: \frac{1}{a^m}=a^{-m}, \ \  \frac{1}{a^{-m}}=a^{m}

    $=\frac{-18 a^{-2} b^{5}a^{4} b^{6}}{-12 }

    $=\frac{-18 a^{-2} a^{4} b^{5} b^{6}}{-12 }

Using exponent rule: {a^m}\cdot{a^n}=a^{m+n}

    $=\frac{-18 a^{(-2+4)} b^{(5+6)}}{-12 }

   $=\frac{-18 a^{2} b^{11}}{-12 }

Divide both numerator and denominator by the common factor –6.

   $=\frac{3 a^{2} b^{11}}{2 }

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}=\frac{3 a^{2} b^{11}}{2 }

Therefore, \frac{3 a^{2} b^{11}}{2 } is equivalent to the given expression.

Hence Option C is the correct answer.

8 0
3 years ago
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