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kaheart [24]
2 years ago
6

Comparing objects using percentages?How?

Mathematics
1 answer:
NeX [460]2 years ago
6 0
Please clarify your question
You might be interested in
Addison painted her room. She had 50 square meters to paint, and she painted at a constant rate. After 2hours of painting, she h
blagie [28]

Answer:

Y  = 50 - 7.5X   if 35 m² Area left to paint after 2 hrs out of total 50m²

Step-by-step explanation:

5 0
3 years ago
Find all x and y intercepts of the graph of the function f(x)= 2x^3+6x^2-2x-6
topjm [15]

9514 1404 393

Answer:

  • y-intercept: (0, -6)
  • x-intercepts: (-3, 0), (-1, 0), (1, 0)

Step-by-step explanation:

We notice the first pair of coefficients is the same as the last pair (with the sign changed). This means we can factor by grouping.

  f(x) = (2x^3 +6x^2) -(2x +6)

  f(x) = 2x^2(x +3) -2(x +3)

  f(x) = 2(x^2 -1)(x +3) = 2(x -1)(x +1)(x +3)

The factors are made to be zero when x is 1, -1, or -3.

The x-intercepts are (1, 0), (-1, 0), (-3, 0).

The y-intercept is the constant, -6.

4 0
2 years ago
How many nanoseconds does it take for a computer to perform one calculation if it performs calculations per second?
igor_vitrenko [27]

I believe the correct question is:

6.7*10^7 calc/sec?

 

So:

1/(6.7 x 10^7) = seconds per calculation

1/(6.7 x 10^7) = 100/(6.7 x 10^9) = 14.9 x 10^-9 seconds per calculation = 14.9 ns

Which is approximately 15 ns

 

Answer:

15 ns

7 0
2 years ago
Apply Newton’s method to estimate the solution of x3 − x − 1 = 0 by taking x1 = 1 and finding the least n such that xn and xn +
ss7ja [257]

Solution :

Given

$f(x)=x^3-x-1, x_1=1$

$f'(x)=3x^2-1$

Let the initial approximation is $x_1 =1$

So by Newton's method, we get

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)},n=1,2,...$

$x_2=x_1-\frac{f(x_1)}{f'(x_1)}=1-\frac{1^3-1-1}{3(1)^2-1}=1.5$

$x_3=1.5-\frac{(1.5)^3-1.5-1}{3(1.5)^2-1}=1.34782608$

$x_4=1.34782608-\frac{(1.34782608)^3-1.34782608-1}{3(1.34782608)^2-1}=1.32520039$

$x_5=1.32520039-\frac{(1.32520039)^3-1.32520039-1}{3(1.32520039)^2-1}=1.32471817$

$x_6=1.32471817-\frac{(1.32471817)^3-1.32471817-1}{3(1.32471817)^2-1}=1.32471795$

$x_5 \approx x_6$ are identical up to eight decimal places.

The approximate real root is x ≈ 1.32471795

∴ x = 1.32471795

4 0
3 years ago
IS THIS CORRECT?
Tems11 [23]
Answer:
Yes
Explanation:
8 0
2 years ago
Read 2 more answers
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