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kaheart [24]
3 years ago
6

Comparing objects using percentages?How?

Mathematics
1 answer:
NeX [460]3 years ago
6 0
Please clarify your question
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The width of a rectangle is 6 2/3 inches. The length of the rectangle is twice its width. What is the perimeter of the rectangle
hichkok12 [17]
A perimeter of a rectangle is:
2(l+w)

They give you the width, but let's convert it to an improper fraction first:
6 \frac{2}{3} =  \frac{20}{3}

The length is twice the width so it is:
\frac{20}{3}*2 =  \frac{40}{3}

Now, we are ready to solve, plug in values in the perimeter formula:
2(  \frac{40}{3}+ \frac{20}{3}) =  2(\frac{60}{3}) =  \frac{120}{3} = 40

So, 40 is your answer.
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Answer:

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Step-by-step explanation:


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Normal form [see attachment]
musickatia [10]

I just did one of these. I guessed that normal form is


x \cos \phi + y \sin \phi -  p = 0


Here' that's


x (\sqrt{3}/2) + y (1/2) - 10 = 0


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Choice b




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2935.88 what is the value of digit 9
frez [133]
900 is the correct answer
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