Answer:
8 nickels
Step-by-step explanation:
Total Amount of Money owned by Jason=$10
1 nickel =$0.05
1 dime=$0.10
1 quarter =$0.25
- Let the number of dimes =d
- Let the number of nickels =n
- Let the number of quarters =q
If there were twice as many dimes as Nickels, then:
Also, there were twice as many quarters as dimes.
Therefore:
0.1d+0.05n+0.25q=100
Substituting d=2n and q=2d into the above relations
0.1(2n)+0.05n+0.25(2d)=10
0.2n+0.05n+0.25(2(2n))=10
0.2n+0.05n+1n=10
1.25n=10
n=8
q=2d=2X16=32
d=2n=2X8=16
Jason had 8 nickels
<span>Sin(m)= 4.5/5.14
Cos(m)= 2.5/5.14
Tan(m)=4.5/5.14
Sin(A)=2.5/5.14
Cos(A)=4.5/5.14
Tan(A)=5.14/4.5</span>
Answer:
50,000,000
Step-by-step explanation:
10,000,000 has 7 0's I just counted backward from the last three 6x and that gave me the answer of 3,000,000 sorry if it's wrong :c
Answer:
I believe that would be 12 because
Step-by-step explanation:
if 2x - 7y = 10
then if you were to add two to that it would be 12