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jarptica [38.1K]
4 years ago
13

Need help with this

Chemistry
2 answers:
Naddik [55]4 years ago
4 0

Answer:

environmentalism I think

Explanation:

...................

xxMikexx [17]4 years ago
3 0

Answer:

2nd choice answer

Explanation:

thats ez tbh

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A solution of permanganate is standardized by titration with oxalic acid, . To react completely with mol of oxalic acid required
Zielflug [23.3K]

Answer:

M=0.120M

Explanation:

Hello,

In this case, the undergone chemical reaction is:

MnO_4^-(aq)+H_2C_2O_4(aq)\rightarrow Mn^{+2}+CO_2

In such a way, the acidic redox balance turns out:

(Mn^{+7}O_4)^-+5e^-+8H^+\rightarrow Mn^{+2}+4H_2O\\H_2C_2O_4\rightarrow2CO_2+2H^++2e^-

Which leads to the total balanced equation as follows:

2(MnO_4)^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow2Mn^{+2}(aq)+8H_2O(l)+10CO_2(g)

Thus, as the mass of oxalic acid is not given, one could suppose a value of 1 g (which you can modify based on the actual statement) in order to compute the oxalic acid moles as shwon below:

1gH_2C_2O_4*\frac{1molH_2C_2O_4}{90.04gH_2C_2O_4} *\frac{2mol(MnO_4)^-}{5molH_2C_2O_4} =0.00444mol(MnO_4)^-

Whereby the molality results:

M=\frac{0.00444mol(MnO_4)^-}{0.03702L} =0.120M

Remember you can modify the oxalic acid mass as you desire.

Best regards.

5 0
4 years ago
How many grams of NH3 can be produced from 2.27mol of N2 and excess H2.
Diano4ka-milaya [45]
The reaction formula of this is N2 + 3H2 = 2NH3. So the ratio of mol number of N2 and NH3 is 1:2. The mol number of NH3 is 2.27*2=4.54 mol. So the mass is 4.54*17=77.18 g.
3 0
4 years ago
A chemist dissolves 398. Mg of pure hydrochloric acid in enough water to make up 210. ML of solution. Calculate the pH of the so
Setler [38]

Answer:

THE pH OF THE SOLUTION IS 1.28

Explanation:

Step 1: Calculate the mass concentration of HCl

398 mg in 210 mL

1 L = 10^3 mL

1 g = 10^3 mg

398 *10^-3 g in 210 *10^-3 L

398 *10^-3 in 0.210 L

mass concentration = (0.398 * 1/ 0.210) g/dm3

= 1.895 g/dm3

Step 2: calculate the molar concentration

Molar mass of HCl = ( 1 + 35.5) = 36.5 g/mol

Molar concentration = mass concentration / RMM

Molar conc. = 1.895 / 36.5

Molar conc. = 0.0519 mol/dm3

So therefore, the molar concentartion of the solution is equal to the concentration of HCl.

In other words, [HCl] = 0.0519 mol/dm3

This shows that at 1 L of this solution contains 0.0519 moles of HCl

Step 3: write the dissiociation equation of HCl in water

HCl(aq) + H2O(l) --------> H30^+ (aq) + Cl- (aq)

Since HCl is a strong acid, it will dissociate completely in water forming the above products.

So we can say that:

[H3O+] = [HCl] = 0.0519 moles/ dm3

Step 4: calculate the pH

pH = -log[H3O+]

pH = -log (0.0519)

pH = 1.28(3 significant decimal place)

The pH of the solution is 1.28

6 0
3 years ago
Which of the following is a synthesis reaction?
blsea [12.9K]
Number 1 is a synthesis reaction because two compounds/elements are coming together to form one compound
5 0
3 years ago
In order to complete his research project, Roger needs to make a mixture of 86 mL of a 36% acid solution from a 39% acid
Zina [86]

The volume of the 39% acid solution that Roger needs to use to make a mixture of 86 mL of a 36% acid solution is 74.27 mL.

The mixture of the acids solutions is given by:

CV = C_{1}V_{1} + C_{2}V_{2}    (1)      

Where:

C: is the concentration if the mixture = 36%  

V: is the total volume of the mixture = 86 mL

C₁: is the concentration of acid 1 = 39%

V₁: is the volume if acid 1 =?

C₂: is the concentration of acid 2 = 17%

V₂: is the volume of acid 2

The sum of V₁ and V₂ must be equal to V, so:

V = V_{1} + V_{2}

V_{2} = V - V_{1}  (2)

By entering equation (2) into (1), we have:

CV = C_{1}V_{1} + C_{2}(V - V_{1})

36\%*86 mL = 39\%*V_{1} + 17\%(86 mL - V_{1})

Changing the percent values to decimal ones:

0.36*86 mL = 0.39*V_{1} + 0.17(86 mL - V_{1})  

Now, by solving the above equation for V₁:

V_{1} = 74.27 mL  

Therefore, the volume of the 39% acid solution is 74.27 mL.

       

To learn more about mixture and solutions, go here: brainly.com/question/6358654?referrer=searchResults

I hope it helps you!  

         

7 0
3 years ago
Read 2 more answers
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