Question

In order to complete his research project, Roger needs to make a mixture of 86 mL of a 36% acid solution from a 39% acid

Answer 1

We have that the volume of the 39% acid solution that Roger needs to use to make the mixture.

x=74mL

From the question we are told that

Roger needs to make a mixture of 86 mL of a 36% acid solution from a 39% acid  solution and a 17% acid solution.

Hence

86 - x of the 17\% acid solution is taken by Rogers

Generally the equation for the mixture concentration is mathematically given as

C_m=\frac{39% solution concentration x volume of solution x 17% solution conc x volume of solution taken}{volume of solution mixture}

36 =\frac{ (39 * x + 17 * (86-x)) }{ 86}

x=74mL

For more information on this visit

brainly.com/question/17756498?referrer=searchResults

Answer 2

The volume of the 39% acid solution that Roger needs to use to make a mixture of 86 mL of a 36% acid solution is 74.27 mL.

The mixture of the acids solutions is given by:

$CV = C_{1}V_{1} + C_{2}V_{2}$    (1)      

Where:

C: is the concentration if the mixture = 36%  

V: is the total volume of the mixture = 86 mL

C₁: is the concentration of acid 1 = 39%

V₁: is the volume if acid 1 =?

C₂: is the concentration of acid 2 = 17%

V₂: is the volume of acid 2

The sum of V₁ and V₂ must be equal to V, so:

$V = V_{1} + V_{2}$

$V_{2} = V - V_{1}$  (2)

By entering equation (2) into (1), we have:

$CV = C_{1}V_{1} + C_{2}(V - V_{1})$

$36\%*86 mL = 39\%*V_{1} + 17\%(86 mL - V_{1})$

Changing the percent values to decimal ones:

$0.36*86 mL = 0.39*V_{1} + 0.17(86 mL - V_{1})$  

Now, by solving the above equation for V₁:

$V_{1} = 74.27 mL$  

Therefore, the volume of the 39% acid solution is 74.27 mL.

       

To learn more about mixture and solutions, go here: brainly.com/question/6358654?referrer=searchResults

I hope it helps you!