Question

Please show work on how to get to the answer. When the diameter of a vessel is increased by 2 times, the flow will :

Answer 1

Answer:

(a) Increase 16 times

Explanation:

According to the Poiseuille flow equation the rate of flow of fluid is directly related to four time square of the radius of the vessel.

$F\alpha r^{4}$

Here, F is the rate of flow, and r is the radius of vessel.

Now according to the question diameter is increased by 2 times then radius is also increased by two times than radius becomes 2r.

So put this value in the flow equation.

$F\alpha (2r)^{4}\\F\alpha 16r^{4}$

Therefore, the rate of flow is increased by 16 times.