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Bond [772]
3 years ago
6

A 60.0 kg girl stands up on a stationary floating raft and decides to go into shore. She dives off the 180 kg floating raft with

a velocity of 4.0 m/s [W]. Ignore the substantial friction real objects in water experience.
A) What is the momentum of the girl as she is diving?
B) What is the momentum of raft as the girl is diving?
C) What is the final speed of the raft just after the girl dives?
Physics
1 answer:
lord [1]3 years ago
6 0
Momentum, p = m.v
m of the girl = 60.0 kg
m of the boat = 180 kg
v of the girl = 4.0 m/s

A) Momentum of the girl as she is diving:
p = m.v = 60.0 kg * 4.0 m/s = 24.0 N/s

B) momentum of the raft = - momentum of the girl = -24.0 N/s

C) speed of the raft

p = m.v ; v = p/m = 24.0N/s / 180 kg = -0.13 m/s [i.e. in the opposite direction of the girl's velocity]
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Answer:

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See the answer below

Explanation:

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A

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<u>Explanation:</u>

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Problem 21-40a:
Greeley [361]

Answer:

Part a)

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Part b)

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here we have

q = 1.6 \times 10^{-19}C

E = 153 N/C

now force is given as

F = (1.6 \times 10^{-19})(153) = 2.45 \times 10^{-17} N

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F_g = mg

F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N

now the ratio of two forces is given as

\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}

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Part b)

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here we have

q = 3.37 \times 10^{-4} C

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A 4-kg object is moving with a speed of 5 m/s at a height of 2 m. The kinetic
tatyana61 [14]

Hello!

\large\boxed{KE = 50J}

Use the formula for kinetic energy:

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KE = \frac{1}{2} (100)\\\\KE = 50 J

7 0
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