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Nitella [24]
3 years ago
12

What particular problem is the topic of the essay and what is the author’s main contention about how the Constitution addresses

this problem? (Federalist No. 10 Papers)
Physics
1 answer:
-BARSIC- [3]3 years ago
5 0
Idkkkkkk omgg i canttt idkkk helpp meee with
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The force F shown in Figure 4.30 has a moment of 40 Nm about the pivot. Calculate the magnitude
salantis [7]

\boxed{\sf \tau=rFsin\theta}

Put values

\\ \rm\hookrightarrow 40=2Fsin40

\\ \rm\hookrightarrow Fsin40=20

\\ \rm\hookrightarrow 0.64F=20

\\ \rm\hookrightarrow F=31.25N

8 0
3 years ago
A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. It begins the trip traveling 120 m/s and decelerates to
podryga [215]
I believe it is -1.11 m/s^2. I will let you know if its correct
7 0
3 years ago
Read 2 more answers
A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provid
Sergeeva-Olga [200]

Answer:

8.37*10^5 rpm

Explanation:

Given that rotational kinetic energy = 4.66*10^9J

Mass of the fly wheel (m) = 19.7 kg

Radius of the fly wheel (r) = 0.351 m

Moment of inertia (I) = \frac{1}{2} mr ^2

Rotational K.E is illustrated as (K.E)_{rt} = \frac{1}{2} I \omega^2

\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }

\omega = \sqrt{\frac{2(KE)_{rt}}{1/2 mr^2} }

\omega = \sqrt{\frac{4(K.E)_{rt}}{mr^2} }

\omega = \sqrt{\frac{4*4.66*10^9J}{19.7kg*(0.351)^2} }

\omega = 87636.04

\omega = 8.76*10^4 rad/s

Since 1 rpm = \frac{2 \pi}{60}  rad/s

\omega = 8.76*10^4(\frac{60}{2 \pi})

\omega = 836518.38

\omega = 8.37 *10^5 rpm

3 0
3 years ago
studies show that the ocean surface temperature is increasing which of the following is a possible consequences
katen-ka-za [31]
One possible consequence is that the warmer temperature cause the polar ice to melt even faster
6 0
3 years ago
What's a streak plate?
andrew-mc [135]
An unglazed piece of porcelain, used to test the characteristic streak of minerals by rubbing the mineral across the tile. Streak plates have a hardness of about 6.5 on the Mohs scale and cannot be used for testing harder minerals.
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3 years ago
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