155>_ 6.50*16.50 the inequality it less then or equal too
I thin it is none, because you are supposed to distribute to all terms not just one.
Assuming that these are seperate equations:
<h3>Problem 1: x^2-5x-6</h3><h3>Problem 2: x^2+3x-40</h3><h3>Problem 3: x^2-7x-30</h3>
Problem 1:
1) Use the sum-product pattern.
x² - 5x - 6
x² + x - 6x - 6
2) Common factor from the two pairs.
x² + x - 6x - 6
x (x + 1) - 6 (x + 1)
3) Rewrite in factored form.
x (x + 1) - 6 (x + 1)
(x - 6) (x + 1) ----> Answer
Problem 2:
1) Use the sum-product pattern.
x² + 3x - 40
x² + 8x - 5x - 40
2) Common factor from the two pairs.
x² + 8x - 5x - 40
x (x + 8) - 5 (x + 8)
3) Rewrite in factored form.
x (x + 8) - 5 (x + 8)
(x - 5) (x + 8) ----> Answer
Problem 3:
1) Use the sum-product pattern.
x² - 7x - 30
x² + 3x - 10x - 30
2) Common factor from the two pairs.
x² + 3x - 10x - 30
x (x + 3) - 10 (x + 3)
3) Rewrite in factored form.
x (x + 3) - 10 (x + 3)
(x - 10) (x + 3) ----> Answer
Cheers,
ROR
Answer:
Value of stamp collection = (45b + 43) cents
Step-by-step explanation:
What we have here is as follows;
if there are x 3-cent stamps, then there are 4x 10-cent stamps
So the number of 2-cent stamps is 1 less than 3 cent stamps and that will be x-1 2 cent stamps
Number of 2 cents stamps = b
This means that x-1 = b
Thus, x = b + 1
So the value of the stamp collection is as follows;
x 3 cents stamps = 3(b+ 1) = 3b + 3 cents
4x 10 cents stamps = 10(4(b + 1)) = 10(4b + 4) = 40b + 40
value of the 2 cents stamp = 2b cents
Total value is thus;
2b + 40b + 40 + 3b + 3 = (45b + 43) cents
Answer: 8/5
Step-by-step explanation:
2^3 = 2*2*2 = 8
Therefore, you are evaluating 32/(8+12)
= 32/20
= 8/5