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castortr0y [4]
2 years ago
15

In question 15 what is the area of the triangle when its height is 6 cm?

Mathematics
2 answers:
xz_007 [3.2K]2 years ago
6 0

Answer:

99

Step-by-step explanation:

If you do that math then you get 99

Mariana [72]2 years ago
3 0

Answer:

a =  \frac{1}{2} (5h + 3)h \\  =  \frac{1}{2} (5 \times 6 + 3)6 \\  =  \frac{1}{2} (33 \times 6) \\  =  \frac{1}{2}  \times 198 \\  a= 99

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2 years ago
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Monica paid sales tax of $1.60 when she bought a new bike helmet. If the sales tax rate was 8%, how much did the store charge fo
Lapatulllka [165]
To find the total from the percent part you have, you divide the part by the percentage.
1.50÷0.05=30
The total is $30
The total the store charged, including sales tax, is $31.50.
5 0
2 years ago
Which of the followings explains the difference between a regular subquery and a correlated subquery?
Fynjy0 [20]
Correlated means that they relate so probably this might help
5 0
3 years ago
Find the value of X and Y.
Elis [28]

Answer:x=63.4° y= 8.16

Step-by-step explanation:

5 0
3 years ago
If A=(0,0) and B=(8,2), what is the length of AB
NeX [460]

Answer:

\boxed{\sf Distance_{AB}= 8.24 \ units }

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , <u>A(</u><u>0</u><u>,</u><u>0</u><u>)</u><u> </u>and <u>B(</u><u>8</u><u>,</u><u>2</u><u>)</u> . The distance between the two points can be found out using the<u> </u><u>Distance</u><u> Formula</u><u> </u>, which is ,

<em>Distance Formula:- </em>

\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}

Therefore on substituting the respective values ,we can find the Distance as ,

\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}

<u>Simpl</u><u>i</u><u>fy </u><u>the </u><u>brackets</u><u> </u><u>,</u>

\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}

Square the numbers inside the squareroot ,

\sf\longrightarrow Distance =\sqrt{ 64 + 4}

Add the numbers inside the squareroot ,

\sf\longrightarrow Distance = \sqrt{68}

Find the value of squareroot,

\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}

<u>Hence</u><u> the</u><u> </u><u>distance</u><u> between</u><u> the</u><u> two</u><u> points</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>2</u><u>4</u><u> </u><u>units </u><u>.</u>

3 0
2 years ago
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