All categories

2 years ago

Find the equation of the line shown

Mathematics

1 answer:

Alenkinab [10]2 years ago

7 0

Answer:

y = -x + 9.

Step-by-step explanation:

The slope = rise run

= 9 /-9

= -1.

The y intercept is at y = 9 so the equation is:

y = -x + 9.

You might be interested in

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0

2 years ago

FINAL EXAM QUESTION 2 HELP! I HAVE 50 QUESTIONS

NARA [144]

Answer:

I think the second one

Step-by-step explanation:

Zero is not a natural number.

It is an integer, rational number ,and whole number

3 0

2 years ago

A postcard has an area of 10 square inches. Two enlargements of the postcard have areas of 40 square inches and 160 square inche

insens350 [35]

Answer:

Step-by-step explanation:

3 0

3 years ago

Is 0.35 a rational or irrational number

kupik [55]

Answer:

I think its rational

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Why did the architects design Savannah on a grid system?

Gwar [14]

To create a flexible street/block pattern that would accommodate a range of densities and residential and recreational uses, the Canadian planners adapted the street grid of Savannah to allow development of individual but continuous neighborhoods.

The original plan actually called for six squares, and as the city grew the grid of wards and squares was extended so that 33 square.

8 0

2 years ago

Find the equation of the line shown​

Find the equation of the line shown