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Darina [25.2K]
3 years ago
15

There are 2 red pens, 3 blue pens, 1 black pen, and 4 green pens in a desk drawer. You randomly choose one. Find each probabilit

y as a FRACTION in SIMPLEST FORM. Total Pens: __________ 1) P (red) ____________ 2) P (black) ____________ 3) P (purple) ____________ 4) P (not green) ____________ 5) P (black or red) __________ 6) P (orange) _________
Mathematics
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

total = 10

1. 1/5

2. 1/10

3. 0/10

4. 3/5

5. 3/10

6. 0/10

Step-by-step explanation:

total;

The sum of all pen types is: 2 + 3 + 1 + 4 = 10

Pen types are:

   red

   blue

   black

   green

1. P (red)

There are 2 red pens, so the fraction is 2/10 which when simplified is 1/5

2. P (black)

There is one black pen, so simplified it will be 1/10

3. P (purple)

There are no purple pens, so its just 0/10

4. P (not green)

There are ten pens total. 4 of them are green, so we subtract the number of green pens to the number of pens total, 10 - 4 = 6

So 6/10 which simplified is 3/5

5. P (black or red)

We find the sum of red and black pens, so its 3/10 which cannot be simplified any further

6. P (orange)

There are no green pens, so its 0/10

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If line A contains the points (3, -4) and (6, -2), and line B contains the points (-1, 5) and (1, 2), prove that the lines are p
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Answer:

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Step-by-step explanation:

Given:

line A - (x₁, y₁) = (3, -4)   and (x₂, y₂) = (6, -2)

line B - (x₁, y₁) = (-1, 5)   and (x₂, y₂) = (1, 2)

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3 years ago
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