A translation occurred that moved 4 units left and 3 units up. If Point A was at ( -3, -2 ), what are the coordinates of A'?

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

Cara saw an advertisement claiming 5 out of 6 students prefer talking on the phone over texting. She predicts that 500 out of 60

Sever21 [200]

5/6 is not the definite ratio, when you take a larger sample size it could be off by a bit like 499/600 or 501/600

8 0

3 years ago

Solve for x. −18 = −2/3 x

vredina [299]

Answer:

x = 27

Step-by-step explanation:

To isolate x, we can multiply it by the reciprocal of the fraction (-3/2). We do the same to the -18.

Through cross-multiplication, -18/1 x -3/2 simplifies into -9/1 x -3/1 (because 2 goes into 2 once and 2 goes into -18 -9 times).

-9 x -3 = 27; therefore, x = 27

7 0

4 years ago

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Select the expression in terms of n

Bumek [7]

Answer:

2n - 11

Step-by-step explanation:

Note there is a common difference d between consecutive terms of the sequence, that is

d = - 7 - (- 9) = - 5 - (- 7) = - 7 + 9 = - 5 + 7 = 2

This indicates the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 9 and d = 2, thus

$a_{n}$ = - 9 + 2(n - 1) = - 9 + 2n - 2 = 2n - 11

6 0

3 years ago

If 3x + 6 = 213x plus 6 equals 21, what does x + 2x plus 2 equal?

Ludmilka [50]

Answer:

17

Step-by-step explanation:

PLS GIVE BRAINLIEST

5 0

3 years ago

Read 2 more answers