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miskamm [114]
3 years ago
8

Two charged particles are placed 2.0 meters apart. the first charge is +2.0 e-6 c and the second charge is +4.0 e-6

Physics
1 answer:
Yakvenalex [24]3 years ago
7 0
The Coulomb force between two charges is defined as: Fc=(k*Q₁*Q₂)/r² where k=9*10^9 N m² C⁻², Q₁ and Q₂ are charges and r is the distance between those charges. 
In our case:

Q₁=2*10^-6 C
Q₂=4*10^-6 C
r=2 m

Now we simply plug in the numbers into the equation:

Fc={(9*10^9)*(2*10^-6)*(4*10^-6)}/2^2=0.018 N

The Coulombs force between the two positive charges is Fc=0.018 N and it is a repulsive force because both charges are positive.
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What is the magnitude of g at a height above Earth's surface where free-fall acceleration equals 6.5m/s^2?
prohojiy [21]

You've given the answer, right there in your question.

The "magnitude of gravity" is described in terms of the acceleration
due to it, and you just told us what that is.

We can also notice that the figure you gave is about 0.66 of the
acceleration due to gravity on the Earth's surface. That tells us that
the distance from the Earth's center at that height is about 

                     (1 / √0.66) = 1.23 times

the Earth's radius, so the height is about  910 miles above the surface.


7 0
3 years ago
A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?
Galina-37 [17]

Answer:

<h2>109.52 Hz</h2>

Explanation:

The frequency of the wave when given it's velocity and wavelength only can be found by using the formula

f =  \frac{c}{ \lambda}  \\

where

c is the velocity of the wave in m/s

\lambda is the wavelength in meters

From the question we have

c = 230 m/s

\lambda = 2.1 m

f =  \frac{230}{2.1}  = 109.523809... \\

We have the final answer as

<h3>109.52 Hz</h3>

Hope this helps you

3 0
3 years ago
A car has a applied force of 120 N and experiences a friction force of 20 N. The mass is 20 kg. The acceleration is
GrogVix [38]
Acceleration = 100/20 = 5 m/s^2
4 0
3 years ago
Read 2 more answers
A 3kg horizontal disk of radius 0.2m rotates about its center with an angular velocity of 50rad/s. The edge of the horizontal di
Lyrx [107]

Answer:

D

Explanation:

From the information given:

The angular speed for the block \omega = 50 \ rad/s

Disk radius (r) = 0.2 m

The block Initial velocity is:

v = r \omega \\ \\  v = (0.2  \times 50) \\ \\  v= 10 \ m/s

Change in the block's angular speed is:

\Delta _{\omega} = \omega - 0 \\ \\ = 50 \ rad/s

However, on the disk, moment of inertIa is:

I= mr^2 \\ \\ I = (3 \times 0.2^2) \\ \\ I = 0.12 \ kgm^2

The time t = 10s

∴

Frictional torques by the wall on the disk is:

T = I \times (\dfrac{\Delta_{\omega}}{t}) \\ \\ = 0.12 \times (\dfrac{50}{10})  \\ \\ =0.6 \ N.m

Finally, the frictional force is calculated as:

F = \dfrac{T}r{}

F= \dfrac{0.6}{0.2} \\ \\ F = 3N

8 0
3 years ago
Describe why chemical bonding occurs. Give two examples of how<br> bonds can form.
Vladimir [108]

Explanation:

Chemical bonding results from attractive forces that joins chemical species.

  • Noble gases show no tendency to combine with themselves or with other kinds of atoms because of their completely filled outer energy levels.
  • The driving force for most interatomic bonding is the tendency to have completely filled outer energy levels just like the inert gases.
  • The stable configuration can be attained by losing or gaining of electrons or sharing of pairs of electrons.

Two examples of how bonds form:

Bonds can be formed by:

  1. Losing and gaining of electrons to form electrovalent or ionic bonds.
  2. Sharing of electrons to form covalent bonds.

Learn more:

Ionic bonds brainly.com/question/6071838

#learnwithBrainly

6 0
3 years ago
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