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Amanda [17]
3 years ago
7

A 12 N force is used to pull a wagon 10 m to the left in 15 seconds. Which of the following represents the magnitude of the forc

e?
12 N
10 m
left
15 seconds



Jody drives 120 miles south from Kingston, NY to Princeton, NJ. If she drives 60 mph, how long will it take her to make the trip?
1 hour
2 hours
4 hours
cannot be determined



Jeremiah is riding his bicycle to the east. It takes him 10 seconds to change his velocity from 10 m/s to 15 m/s. What is Jeremiah's acceleration?
5 m/s
5 m/s/s
0.5 m/s
0.5 m/s/s
Physics
2 answers:
Lana71 [14]3 years ago
7 0

1. - 12N

2.- 2 hours

3. - 0.5 m/s/s

Nadya [2.5K]3 years ago
4 0

Answer:

12 Newtons

Explanation:

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A high powered rifle can shoot a bullet at a speed of 1500 mi/hr. On the moon, with almost no atmosphere and an acceleration due
Amiraneli [1.4K]

Answer:

Explanation:

On the Moon :----

1500 x 1.6 = 2400 m /s is initial velocity of bullet .

g = 1.6 m /s²

v = u - gt

0 = 2400 - 1.6 t

t = 1500 s

This is time of ascent

Time of decent will also be the same

Total time of flight = 2 x 1500 = 3000 s

On the Earth : ---

v = u - a₁ t

0 = u - a₁ x 18

u = 18a₁

v² = u² - 2 x a₁ x 2743.2

0 = (18a₁ )² - 2 x a₁ x 2743.2

a₁ = 16.93

For downward return

s = ut + 1/2 a₂ x t²

2743.2 = 0 + .5 x a₂ x 31²

a₂ = 5.7 m /s²

If d be the deceleration produced by air

g + d = 16.93 ( during upward journey )

g - d = 5.7

g = (16.93 + 5.7) / 2  

= 11.315 m / s

d = 5.6 m /s²

So air is creating a deceleration of 5.6 m /s².

6 0
3 years ago
. Strong language often means
san4es73 [151]
I would say that strong language typically reveals strong feelings: strong language would reveal desperation, or very strong feelings: weak feelings would not demand it, and would be more likely accompanied by more controlled behavior.
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Zero, a hypothetical planet, has a mass of 5.3 x 1023 kg, a radius of 3.3 x 106 m, and no atmosphere. A 10 kg space probe is to
Andrej [43]

(a) 3.1\cdot 10^7 J

The total mechanical energy of the space probe must be constant, so we can write:

E_i = E_f\\K_i + U_i = K_f + U_f (1)

where

K_i is the kinetic energy at the surface, when the probe is launched

U_i is the gravitational potential energy at the surface

K_f is the final kinetic energy of the probe

U_i is the final gravitational potential energy

Here we have

K_i = 5.0 \cdot 10^7 J

at the surface, R=3.3\cdot 10^6 m (radius of the planet), M=5.3\cdot 10^{23}kg (mass of the planet) and m=10 kg (mass of the probe), so the initial gravitational potential energy is

U_i=-G\frac{mM}{R}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{3.3\cdot 10^6 m}=-1.07\cdot 10^8 J

At the final point, the distance of the probe from the centre of Zero is

r=4.0\cdot 10^6 m

so the final potential energy is

U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{4.0\cdot 10^6 m}=-8.8\cdot 10^7 J

So now we can use eq.(1) to find the final kinetic energy:

K_f = K_i + U_i - U_f = 5.0\cdot 10^7 J+(-1.07\cdot 10^8 J)-(-8.8\cdot 10^7 J)=3.1\cdot 10^7 J

(b) 6.3\cdot 10^7 J

The probe reaches a maximum distance of

r=8.0\cdot 10^6 m

which means that at that point, the kinetic energy is zero: (the probe speed has become zero):

K_f = 0

At that point, the gravitational potential energy is

U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{8.0\cdot 10^6 m}=-4.4\cdot 10^7 J

So now we can use eq.(1) to find the initial kinetic energy:

K_i = K_f + U_f - U_i = 0+(-4.4\cdot 10^7 J)-(-1.07\cdot 10^8 J)=6.3\cdot 10^7 J

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2 years ago
X + 10 times X = 50 what is the answer
tia_tia [17]

Answer:

4.54

Explanation:

X+10X=50

11X=50

X=4.54#

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3 years ago
The wavelength of a certain portion of an electromagnetic wave is 314 nm. what is its frequency and classification?
nadezda [96]

The frequency of the electromagnetic wave is 9.55 × 1014 Hz and it is classified as ultraviolet.

<h3>What is meant by electromagnetic waves?</h3>

Electromagnetic waves are forms of energy that are invisible and travel throughout the universe. However, some of the effects of this energy are visible. The light that we see is a component of the electromagnetic spectrum.

Electromagnetic waves, or EM waves, are produced by vibrations between an electric field and a magnetic field. In other words, electromagnetic waves are made up of oscillating magnetic and electric fields.

<h3>How do you calculate the speed of an electromagnetic wave?</h3>

The wavelength and frequency of any periodic wave are used to calculate its speed. v = λf.

In free space, the speed of any electromagnetic wave is equal to the speed of light, c = 3 *108 m/s.

The frequency of the electromagnetic wave is 9.55 × 1014 Hz and it is classified as ultraviolet.

To learn more about electromagnetic wave refer to:

brainly.com/question/25847009

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5 0
1 year ago
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