1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisabon 2012 [21]
2 years ago
11

Solve for g.-6g – 5 + 5 = 2 – 8g

Mathematics
2 answers:
sergey [27]2 years ago
6 0

Answer:

8.875

Step-by-step explanation:

The +5 and -5 cancel, so you are left with -69=2-8g. Subtract two on both sides to get -71=-8g then divide both side by -8 to get g=8.875.

svet-max [94.6K]2 years ago
3 0

Answer:

g=71 / 8

Step-by-step explanation:

- 69 - 5 + 5 = 2 - 8g

- 69 = - 8g + 2

- 69 + (- 2 = (- 8g + 2 ) + - 2)

- 71 = ( - 8g + 2) - 2

- 71 = - 8g + 2 - 2

-71 = 8g

- 8g = - 71

8g / 8 = 71 / 8

g = 71 / 8

You might be interested in
Q26. Look at the image below
Elan Coil [88]

Answer:

A

Step-by-step explanation:

read the question properly

4 0
3 years ago
Help asappppp? i’m having trouble on wat the 1/4 point is
blagie [28]

Answer:

  (-14, 5.5)

Step-by-step explanation:

Perhaps the easiest way to find the 1/4 point is to find (x, y), then find the midpoint between that and M.

  (x, y) = 2M -(13, 25) = 2(-5, 12) -(13, 25) = (-23, -1)

Then the 1/4 point is ...

  ((-23, -1) +M)/2 = ((-23, -1) +(-5, 12))/2 = (-28, 11)/2 = (-14, 5.5)

_____

If we call the end points A(x, y) and B(13, 25), then we know ...

  M = (A+B)/2

  A = 2M -B . . . . we'll need this in a bit

and the 1/4 point Q is such that ...

  (Q -A)/(B -A) = 1/4

  4Q -4A = B -A . . . . cross multipliy

  Q = (B +3A)/4 = (B +3(2M -B))/4 = (6M -2B)/4 . . . . solve for Q

  Q = (3M -B)/2 . . . . reduce the fractions

  Q = (3(-5, 12) -(13, 25))/2 = (-28, 11)/2 = (-14, 5.5) . . . as above

6 0
2 years ago
For safety reasons, four different alarm systems were installed in the vault containing the safety deposit boxes at a beverly hi
AleksAgata [21]
The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system

Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
1 - 0.00000001 = 0.99999999

The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
7 0
2 years ago
Divide, need help again ppl, thanks!​
7nadin3 [17]

Answer:

<h2>√2,2√4</h2>

Step-by-step explanation:

<h2>√2,√8</h2><h2>√2,√4×2</h2><h2>√2,√2×2×2</h2><h2>√2,√2×2 2</h2><h2>√2,2√4 answer</h2>
4 0
1 year ago
Read 2 more answers
A taxi in myrtle beach charges $2 per mile and $1 per person. If a taxi cab ride for 2 people cost $12, how far did the taxi cab
GarryVolchara [31]

Answer:

I belive the answer is 5

Step-by-step explanation:

$12- $2 for ppl= $10

$10÷$2 per mile = 5

4 0
3 years ago
Other questions:
  • This box has the same length , width, and height as the 2 basketballs. Which expression gives the volume of the empty space enci
    8·2 answers
  • If the perimeter of a rectangle is 38 inches how tall is it
    12·1 answer
  • Sean has $75 to spend on CDs. If each CD costs $6.98, about how many CDs can he buy?
    8·2 answers
  • Find m∠USW if m∠USW = 7x - 34 and m∠TSR = 4x + 9.
    7·1 answer
  • Tom buys a pen holder for $5 and 10 pens for $1 each. The sales tax for the whole purchase is $3.
    15·2 answers
  • The total scores on the Medical College Admission Test (MCAT) in 2013 follow a Normal distribution with mean 25.3 and standard d
    12·1 answer
  • Help mee!!!!!!!!!!!!
    14·2 answers
  • Determine whether the ordered pair (6, 1) satisfies the equation y = 10 - 4x
    12·1 answer
  • PLEASE HELP me cause i suck at math
    11·1 answer
  • Can you please help on this problem
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!