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romanna [79]
3 years ago
8

a toy store marks up every toy by 15% in january. how much does a toy cost during January? use p for the price in December

Mathematics
1 answer:
rjkz [21]3 years ago
8 0

Answer:

D   1.15p

Step-by-step explanation:

Since the price is marked up 15%, you add 15% to the original price, which is p.

15% = .15

p = 1p

1p + .15p = 1.15 p

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Solve for x please thanks​
N76 [4]

Answer:

32

Step-by-step explanation:

So, lets go over what we know:

The equation to find x is the same on both sides.

Now, lets find this equation:

So, the total area of the two lines on the left side of the triangle are 24.

Lets first subtract the first line from the total of the two lines to find the value of the second line:

24-3

=

21.

Now that we know the value of the 2nd line is 21. lets divide it by the first line(3) to find the scale factor:

21/3

=

7

So the scale factor is 7!

Lets plug this in for x.

We know that the first line is 4.

The second line is 7x bigger than 4.

So we can calculate this as:

7x4

=

28

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This is your answer!

Hope it helps! :)

6 0
3 years ago
Complete the following by filling in the blanks.
max2010maxim [7]

Answer:

0.5 x 2 = 1 so therefore area height base =  1in

Hope this helps ^^

4 0
3 years ago
Read 2 more answers
WILL MARK BRAINLYEST
Nadusha1986 [10]

Answer:

17576

Step-by-step explanation:

As L can be anything from A to Z , there are 26 combinations for that and as repetition is allowed, for second and third letters, we again have 26 combinations available and thus 26×26×26=17576 combinations for letters.

5 0
3 years ago
F(x) = 4√(2x³-1)<br> F'(x) =.....?
goldfiish [28.3K]

Answer:

\large\boxed{f'(x)=\dfrac{12x^2}{\sqrt{2x^3-1}}}

Step-by-step explanation:

f(x)=4\sqrt{2x^3-1}=4\left(2x^3-1\right)^\frac{1}{2}\\\\f'(x)=4\cdot\dfrac{1}{2}(2x^3-1)^{-\frac{1}{2}}\cdot3\cdot2x^2=\dfrac{12x^2}{(2x^3-1)^\frac{1}{2}}=\dfrac{12x^2}{\sqrt{2x^3-1}}\\\\\text{used}\\\\\sqrt{a}=a^\frac{1}{2}\\\\\bigg[f\left(g(x)\right)\bigg]'=f'(g(x))\cdot g'(x)\\\\\bigg[nf(x)\bigg]'=nf'(x)\\\\(x^n)'=nx^{n-1}

6 0
3 years ago
An artist sells original hand painted greeting cards. He makes $2.50 profit on a small card and $4.00 profit on a large card. He
Marysya12 [62]
Since he sells 5 large cards for every 2 small, we can multiply the number of small cards he needs to sell by 2.5 to find how many large cards he needs to sell.

So let x=the number of small cards sold, and 2.5x=the number of large cards sold

The equation is:Total profit=x+(2.5x)

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So he needs to sell 800 small cards.

Multiply that by that 2.5.

And he needs to sell 2000 large cards.

3 0
3 years ago
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