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dimulka [17.4K]
3 years ago
10

the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm, what is the radiusof the small

circle?
Mathematics
2 answers:
Orlov [11]3 years ago
8 0

C1/C2 =  2/3

 2pi r1 / 2pi r2 = r1/r2 = 2/3

r1/39 = 2/3

r1 = 39*2/3 = 26

So, your answer is 26cm

Trava [24]3 years ago
6 0

Answer:

r_{1} = 26.

Step-by-step explanation:

Given : the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm,

To find : what is the radius of the small circle.

Solution : We have given that ratio of the circumferences of two circles is 2:3.

Let r_{2}  is radius of larger circle and  r_{1}  is radius of small circle .

Then circumference = \frac{2\pi\ r_{1} }{2\pi\ r_{2}} = \frac{2}{3} .

Solving the above equation

\frac{r_{1}}{r_{2} } =  \frac{2}{3} .

We have given radius of larger circle = 39 then

\frac{r_{1}}{39} =  \frac{2}{3} .

On multiplying both sides by 39.

r_{1} = 39 *\frac{2}{3}.

r_{1} = 13 * 2.

r_{1} = 26.

Therefore, r_{1} = 26.

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Which of the following is a solution of the system 2x + y = 9 and 3x + 5y = 19.​
Nezavi [6.7K]

2x+y=9

3x+5y=19

I will do this problem in 2 ways. I.)Substitution II.)Elimination

Solution I.) Substitution

We can subtract 2x from both sides in the first equation.

y=9-2x

Now we can substitute the y in the second equation with 9-2x

3x+5(9-2x)=19

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-7x=-26

x=26/7

y=9-2(26/7)=11/7

Solution II.)Elimination

We can multiply both side of first equation by 5 to get a 5y in both equations.

10x+5y=45

Now because both are positive 5y we just need to do simple subtraction of the 2 equation, each side respectively.

(10x+5y)-(3x+5y)=45-19

7x=26

x=26/7

2*26/7+y=9

y=11/7

Ultimately you get the same answer, both are viable methods, some problems are faster with one method but I recommend mastering both since they are very useful.

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Answer:

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Step-by-step explanation:

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