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qwelly [4]
3 years ago
14

I don’t get this at alllllll

Mathematics
1 answer:
Orlov [11]3 years ago
6 0
I believe it is A. the |a| show that it can be the opposite as well, and 4*2+8.

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Zero product property:<br><br> (x-4)(-5x+1)=0<br><br> lesser x=<br><br> greater x=
GaryK [48]

Answer:

lesser x= (x-4)greater x=(-5x+1)

5 0
3 years ago
Shannon rolls two number cubes, each numbered one through six. She observes the numbers facing up on each number cube and finds
Natali5045456 [20]

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2 years ago
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PLZ HELP FIND R AND EXPLAIN
4vir4ik [10]

Answer:

r = 46

Step-by-step explanation:

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3 years ago
Simplify square root of 2 over cube root of 2.
Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

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\sqrt[n]{x}  =  {x}^{ \frac{1}{n} }

So you can rewrite the given fraction as

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }  =  {2}^{ \frac{1}{2} -  \frac{1}{3}  }

Since

\frac{1}{2}  -  \frac{1}{3}  =  \frac{3}{6}  -  \frac{2}{6}  =  \frac{1}{6}

the answer is

{2}^{ \frac{1}{6} }  \: or \:  \sqrt[6]{2}

3 0
3 years ago
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Write this second order differential equation as a first order matrix-vector system of differential equations. Show your work in
Mkey [24]

Answer:

See explaination

Step-by-step explanation:

To convert a second-order differential equation into a system of linear differential equation, we have to write y'' as x', for some variable x.

please kindly see attachment for the step by step solution of the given problem.

4 0
3 years ago
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