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3 years ago

I don’t get this at alllllll

Mathematics

1 answer:

Orlov [11]3 years ago

6 0

I believe it is A. the |a| show that it can be the opposite as well, and 4*2+8.

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Notebooks cost a $1.20 each this week and they will be on sale for $0.80 what percentage is the sale

ozzi

We can use algebra.

So, what rate time 1.20 = .80

Let x = the rate (in a decimal form)

1.20x = .80

x = .6666666666

Now, we need to multiply by 100 to get a percentage.

66.66 The price is 66% of the regular price.

They marked it off

33.33%

6 0

3 years ago

Read 2 more answers

Whoever does gets brainest NO JOKE

Kruka [31]

Answer:

x=2475/31 Exact form

x=70.838 Decimal form

x=7026/31 Mixed Number form

i didnt know which one you wanted

3 0

3 years ago

Is this a function?<br>

zmey [24]

Answer:

yes srry if I'm wrong

.................

...

5 0

2 years ago

Enter the y-intercept of the function

Advocard [28]

The y intercept is (0 , 9)

when x is zero, the number in the y value is the y-intercept

8 0

2 years ago

find the value of the trigonometric function sin (t) if sec t = -4/3 and the terminal side of angle t lies in quadrant II

kodGreya [7K]

Answer:

$sin(t) =\frac{\sqrt{7}}{4}$

Step-by-step explanation:

By definition we know that

$sec(t) = \frac{1}{cos(t)}$

and

$cos ^ 2(t) = 1-sin ^ 2(t)$

As $sec(t) = -\frac{4}{3}$

Then

$sec(t) = -\frac{4}{3}\\\\\frac{1}{cos(t)} =-\frac{4}{3}\\\\cos(t) = -\frac{3}{4}$

Now square both sides of the equation:

$cos^2(t) = (-\frac{3}{4})^2$

$cos^2(t) = \frac{9}{16}\\\\$

$1-sin^2(t) =\frac{9}{16}\\\\sin^2(t) =1-\frac{9}{16}\\\\sin^2(t) =\frac{7}{16}\\\\sin(t) =\±\sqrt{\frac{7}{16}}$

In the second quadrant sin (t) is positive. Then we take the positive root

$sin(t) =\sqrt{\frac{7}{16}}$

$sin(t) =\frac{\sqrt{7}}{4}$

8 0

2 years ago