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Elenna [48]
3 years ago
13

The test grades of 10 different students were used to create the box plot above. Which of the following is the median of the set

of grades?
A. 62
B. 80
C. 71
D. 70

Mathematics
2 answers:
nordsb [41]3 years ago
8 0

On a box and Quaker plot the median is the middle dot is the median so 71

lakkis [162]3 years ago
3 0

Answer:

the answer is 71

Step-by-step explanation:

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Please anwser this ASAP
jasenka [17]
It would be 3/1 I think
8 0
3 years ago
Solve for x using distributive property <br><br> 2(x+7)=13<br><br> and<br><br> 5(x-7)=17
Law Incorporation [45]

Answer:

x= −1/2, x=52/5

Step-by-step explanation:

2(x+7)=13

(2)(x)+(2)(7)=13(Distribute)

2x+14−14=13−14

2x=−1

2x/<u><em>2</em></u>=−1/<u>2</u>

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

5(x−7)=17

(5)(x)+(5)(−7)=17(Distribute)

5x+−35=17

5x−35=17

5x−35+35=17+35

5x=52

5x/<u><em>5</em></u>=52/<u>5</u>

4 0
2 years ago
Joshua places the letters in the word SNOWMAN in a bag. A letter is drawn randomly and not replaced. Then another letter is sele
oksano4ka [1.4K]

Answer:

13/42

Step-by-step explanation:

1/7 + 1/6

13/42

7 0
2 years ago
Brainiest for the smart cookie that solves this. It's hard, good luck!
marysya [2.9K]

Answer:

672

Step-by-step explanation:

If there must be at least 4 people in each group, then the number of people in the group for tennis must be 4, 5, or 6.

There are

(10/k)=(10!)/(k!(10−k)!)

ways of choosing k people from a group of 10, and so there are

(10/4)+(10/5)+(10/6)=(10!)/(4!6!)+(10!)/(5!5!)+(10!)/(6!4!)

=2×(10×9×8×7)/(4×3×2×1)+(10×9×8×7×6)/(5×4×3×2×1)

=2×(10×3×1×7)/(1×1×1×1)+(1×3×2×7×6)/(1×1×1×1×1) =420+252=672

5 0
3 years ago
suppose the z-score of your grade in this statistics course turns out to be .97. interpret this z-score.
Anon25 [30]

A z score of 0.97 corresponds with a probability of 83.40%

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean,\sigma=standard\ deviation

From the normal distribution table:

P(z < 0.97) = 0.8340 = 83.40%

A z score of 0.97 corresponds with a probability of 83.40%

Find out more on z score at: brainly.com/question/25638875

5 0
2 years ago
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