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mars1129 [50]
3 years ago
13

Need Help with # 16...............................

Mathematics
2 answers:
Alona [7]3 years ago
8 0

The coefficient for the first y is 1. Second y is 4. Third y is -3.

9966 [12]3 years ago
8 0
I think it is Y to the 7nth power because you do Y to the 5th plus 4y to the 2nd and get 4y to the 7nth but then minus 3y and get 1y to the 7nth. which is equal to Y to the 7nth

Answer Y to the 7nth power
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Write the fraction as an equivalent fraction with the given denominator. 5/6= /18
Troyanec [42]

Answer:

15

Step-by-step explanation:

18 ÷ 6 = 3

5 * 3 = 15

5/6 * 3/3 = 15/18

5 0
3 years ago
I have one more question to go can someone please help me this is really important
Ghella [55]
Answer: 272 square feet
4 0
3 years ago
107+0+39+13 use properties to fin the sum
Vikentia [17]
The answer to the question is 159 all you do is add everything together
6 0
4 years ago
Suppose the weights of tight ends in a football league are normally distributed such that σ2=400. A sample of 11 tight ends was
AlladinOne [14]

Answer:

217.636-1.96\frac{20}{\sqrt{11}}=205.817    

217.636+1.96\frac{20}{\sqrt{11}}=229.455    

So on this case the 95% confidence interval would be given by (205.82;229.46)    

Step-by-step explanation:

Assuming the following data: Weight 150 169 170 196 200 218 219 262 269 270 271

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma= \sqrt{400}= 20 represent the population standard deviation

n=11 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean we can use the following formula:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

The mean calculated for this case is \bar X=217.636

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

217.636-1.96\frac{20}{\sqrt{11}}=205.817    

217.636+1.96\frac{20}{\sqrt{11}}=229.455    

So on this case the 95% confidence interval would be given by (205.82;229.46)    

8 0
4 years ago
Vincent ran 24 laps on monday. this is 66 2/3% of the maximum number of laps he has to run in one day. what is the maximum umber
irakobra [83]
66 2/3% of what is 24...
66.67%x = 24
0.6667x = 24
x = 24 / 0.6667
x = 35.9 rounds to 36 laps
7 0
4 years ago
Read 2 more answers
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