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2 years ago

ANSWER CORRECTLY THIS AND GET 20 AND BRAINLIEST!

Mathematics

1 answer:

son4ous [18]2 years ago

4 0

Sin of <A = Opposite/Hypotenuse
Sin of <A = Y/Z
Sin of <A = 12/13

Answer
C. 12/13 units

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Lerok [7]

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2 years ago

Greetings. As a beginner, I'm struggling a bit to learn calculus. May I know what is the derivative of x to the power 4 step by

elena-14-01-66 [18.8K]

If you're just starting calculus, perhaps you're asking about using the definition of the derivative to differentiate $x^4$ .

We have

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x+h)^4 - x^4}h$

Expand the numerator using the binomial theorem, then simplify and compute the limit.

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x^4+4hx^3 + 6h^2x^2 + 4h^3x + h^4) - x^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} \frac{4hx^3 + 6h^2x^2 + 4h^3x + h^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} (4x^3 + 6hx^2 + 4h^2x + h^3) = \boxed{4x^3}$

In general, the derivative of a power function $f(x) = x^n$ is $\frac{df}{dx} = nx^{n-1}$ . (This is the aptly-named "power rule" for differentiation.)

3 0

2 years ago

bookstore ordered 1,528 packs of pens and 1,823 packs of pencils at the prices shown. how much did the bookstore spend on pens?

IgorC [24]

I found that the given prices are $ 4 per pack of pens and $ 3 per pack of penciles.

The question is how much the bookstore spent on pens.

Then you have to multiply the number packs of pens, which is 1,528, times the price per pack pens which is $ 4.

So, the answer is: 1528 packs of pens * $ 4 / pack of pens = $6112.

8 0

3 years ago

PLEASE HELP ME WITH THXXXXXX:)))))))))

Fantom [35]

1) (-7,2)
y=2, -x+4=11, -x=11-4=7, x=-7

2) (-3,4)
-x+2y=11
y=4, -x+8=11, -x=3, x=-3

3) (1,6)
-x+2y=11
y=6, -x+12=11,-x=-1, x=1

4 0

3 years ago

Nola was selling tickets at the high school dance. At the end of the evening she picked up the cash box and noticed a dollar lyi

Blizzard [7]

Answer:

The $1 belongs to the cash box

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine if the $1 belongs to the cash box or not

Represent singles with s and couples with c.

From the attachment, we have:

$s + c = 47$ --- total attendance

$5s + 4c =200$ --- ticket sold

Solve for s and c.

Make s the subject in (1)

$s = 47-c$

Substitute 47 - c for s in (2)

$5(47 - c) + 4c = 200$

Open bracket

$235 - 5c + 4c = 200$

$235 - c = 200$

$c = 235 - 200$

$c = 35$

This means that the total individual which makes up the couples are 35. This is not possible because couples are in 2's and the total should be an even number.

<em>So, we can conclude that the $1 belongs to the cash box</em>

4 0

2 years ago