ANSWER CORRECTLY THIS AND GET 20 AND BRAINLIEST!

You roll a number cube. What is the probability it will land on a number greater than 5?

olasank [31]

1 out of 6 chances

Explanation: there’s 6 sides of a cube if you mark them 1-6 there only one side that you can land on that is greater then 5 which is six also if you need it in percent it’s 16.6%

5 0

2 years ago

Help! Pls answer correctly!

defon

Answer:

<h3>numbers of Ostrich he keep = 725</h3>

<u>Step-by-step explanation:</u>

Area of field = 30 × 155 + 90 × 45
Area of field = 4650 + 4050
Area of field = 8700 m²

1 ostrich need = 12 m²

numbers of Ostrich = 8700 ÷ 12

numbers of Ostrich = 725

8 0

2 years ago

Which model can be used to subtract 1/2 from 5/6?

Soloha48 [4]

Answer:

2nd one

Step-by-step explanation:

1/2 when multiplied with 3/3 so it has the same denominator is 3/6, the second choice shows 3/6 as a model as well as 5/6 so yea

8 0

3 years ago

A small pizza has an 8-in. Diameter a large pizza has a 15-in. Diameter. The pizzeria charges the same price per square inch for

vlabodo [156]

The cost of large pizza is $24.62, a small pizza has an 8-in. diameter a large pizza has a 15-in. diameter the pizzeria charges the same price per square inch for both pizzas and the small pizza cost $7.

Step-by-step explanation:

The given is,

A small pizza has an 8-inches in diameter

A large pizza has a 15-inches in Diameter

The small pizza cost $7

Step:1

Area of smaller pizza,

$Area, A_{S} = \pi r^{2}$ ...................................(1)

Where, r - Radius of small pizza

From given, $r=\frac{d}{2}$

$= \frac{8}{2}$

r = 4 inches

Equation (1),

$A_{S} = \pi 4^{2}$

$=(3.14)(16)$ ( ∵ $\pi$ =3.14 )

$= 50.24$ Square inches

Step:2

Area of smaller pizza,

$Area, A_{L} = \pi r^{2}$ ...................................(1)

Where, r - Radius of small pizza

From given, $r=\frac{d}{2}$

$= \frac{15}{2}$

r = 7.5 inches

Equation (1),

$A_{S} = \pi 7.5^{2}$

$=(3.14)(56.25)$ ( ∵ $\pi$ =3.14 )

$= 176.625$ Square inches

Step:3

Cost of pizza per square meter,

$= \frac{Cost of small pizza}{Area of small pizza}$

$=\frac{7}{50.24}$

= $ 0.1393 per square meter

$Cost of Larger pizza = Area of Larger pizza$ × $Cost per square meter$

$= (176.625)(0.139331)$

= $24.62

Result:

The cost of large pizza is $24.62, a small pizza has an 8-in. diameter a large pizza has a 15-in. diameter the pizzeria charges the same price per square inch for both pizzas and the small pizza cost $7.

6 0

4 years ago

A company plans to launch a new product. They have traditionally had a 60% success rate with the launch of new products. Market

Juliette [100K]

Answer:

The probability that the product will be successfully launched given that the market test result comes back negative is 0.30.

Step-by-step explanation:

Denote the events provided as follows:

<em>S</em> = a product is successfully launched

<em>P</em> = positive test market result

The information provided is:

P (S) = 0.60

P (P | S) = 0.80

P (P | S') = 0.30

Then,

P (P' | S) = 1 - P (P | S) = 1 - 0.80 = 0.20

P (P' | S') = 1 - P (P | S') = 1 - 0.30 = 0.70

Compute the probability of positive test market result as follows:

$P(P)=P(P|S)P(S)+P(P|S')P(S')$

$=(0.80\times 0.60)+(0.30\times 0.40)\\\\=0.48+0.12\\\\=0.60$

The probability of positive test market result is 0.60.

Then the probability of negative test market result is:

P (P') = 1 - P (P)

= 1 - 0.60

= 0.40

Compute the probability that the product will be successfully launched given that the market test result comes back negative as follows:

$P(S|P')=\frac{P(P'|S)P(S)}{P(P')}$

$=\frac{0.20\times 0.60}{0.40}\\\\=0.30$

Thus, the probability that the product will be successfully launched given that the market test result comes back negative is 0.30.

6 0

3 years ago