The 21st term of the given arithmetic sequence is 83. The nth term of an arithmetic sequence is applied to find the required value where n = 21.
<h3>What is the nth term of an arithmetic series?</h3>
The nth term of an arithmetic sequence is calculated by the formula
aₙ = a + (n - 1) · d
Here the first term is 'a' and the common difference is 'd'.
<h3>Calculation:</h3>
The given sequence is an arithmetic sequence.
3, 7, 11, 15, 19, ....
So, the first term in the sequence is a = 3 and the common difference between the terms of the given sequence is d = 7 - 3 = 4.
Thus, the required 21st term in the sequence is
a₂₁ = 3 + (21 - 1) × 4
⇒ a₂₁ = 3 + 20 × 4
⇒ a₂₁ = 3 + 80
∴ a₂₁ = 83
So, the 21st term in the given arithmetic sequence is 83.
Learn more about the arithmetic sequence here:
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Answer:
300+ 12h=450
12h=150
h=12.5
Step-by-step explanation:
Answer:
Please check the explanation.
Step-by-step explanation:
Given
a)
f(x) + g(x) = (2x - 1) + (2 - x)
= 2x -1 + 2 - x
= x + 1
b)
f(x) - g(x) = (2x - 1) - (2 - x)
= 2x - 1 - 2 + x
= 3x - 3
c)
g(-5) - f(-5)
Putting x = -5 in g(x) = 2 - x
g(x) = 2 - x
g(-5) = 2 - (-5) = 2+5 = 7
Putting x = -5 in f(x) = 2x - 1
f(x) = 2x - 1
f(-5) = 2(-5) - 1
= -10 - 1
= -11
Thus,
g(-5) - f(-5) = 7 - (-11) = 7+11 = 18
d)
f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2
e)
f(g(x)) = f(2-x)
= 2(2-x)-1
= 4-2x-1
= 3-2x
Answer : 11^9
Explanation: when you’re dividing powers, you substract them, so in this case it is 6-2 and you’ll get 11^4. Then you need to multiply, when you’re multiplying you are adding powers. In this case you add 4 and 5 and get 11^9
Answer:
150658743
Step-by-step explanation:
(301 317 167+319)÷2=150658743
