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Tcecarenko [31]
3 years ago
7

How many electrons can fit in the second energy level?

Chemistry
2 answers:
tiny-mole [99]3 years ago
6 0
Electron shell

In chemistry and atomic physics, an electron shell, or a principal energy level, may be thought of as an orbit followed by electronsaround an atom's nucleus. The closest shell to the nucleus is called the "1 shell" (also called "K shell"), followed by the "2 shell" (or "L shell"), then the "3 shell" (or "M shell"), and so on farther and farther from the nucleus. The shells correspond with the principal quantum numbers (n = 1, 2, 3, 4 ...) or are labeled alphabetically with letters used in the X-ray notation (K, L, M, …).

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. The general formula is that the nth shell can in principle hold up to 2(n2) electrons.[1] Since electrons are electrically attracted to the nucleus, an atom's electrons will generally occupy outer shells only if the more inner shells have already been completely filled by other electrons. However, this is not a strict requirement: atoms may have two or even three incomplete outer shells. (See Madelung rule for more details.) For an explanation of why electrons exist in these shells see electron configuration.[2]

The electrons in the outermost occupied shell (or shells) determine the chemical properties of the atom; it is called the valence shell.

Each shell consists of one or more subshells, and each subshell consists of one or more atomic orbitals.

patriot [66]3 years ago
4 0

8 electrons would fit in the 2nd energy level.

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If you dissolve 23 g of ammonium chloride in 500.0 mL of water, what is the molar concentration of the solution?
Burka [1]
Molar concentration is the amount of solute in moles divided by 1 liter of solvent. Then to answer this question, you need to convert the 23g of ammonium chloride into mole unit. Since the mass of nitrogen = 14, helium =1, and chlor= 35.453 then the molecular mass of (NH4)Cl should be: 14+4+35.453= 53.5

Then, the molarity should be: 23g/ (53.5gr/mole)/ (500ml/1000ml)= 0.86molality
7 0
4 years ago
When 2.50 mol of mg3n2 are allowed to react how many moles of h2o also react?
spin [16.1K]

Notice that in the equation given, there is 1 mol of Mg3N2 and 6 mol of H2O. Consequently, the question is requesting, if we took 2.5 mol of Mg3N2, how many mol of H2O would be essential to complete a similar reaction -- in quintessence, multiplying everything by 2.5: 

the solution would be: 6 * 2.5 = 15 mol

7 0
4 years ago
A sample is found to contain 57.2 % N a H C O 3 NaHCOX3 by mass. What is the mass of NaHCO 3 in 4.25 g of the sample
liq [111]

Answer:

The mass of N a H C O 3 present is 2.431 g

Explanation:

The sample contains 57.2 % N a H C O 3  by mass.

To find the mass of N a H C O 3  in the sample, we need to find what the equivalent of 57.2 %.

Mass of N a H C O 3  = Percentage Composition * Mass of sample

Mass of N a H C O 3  = 57.2 / 100     * 4.25

Mass of N a H C O 3   = 2.431 g

The mass of N a H C O 3 present is 2.431 g

3 0
4 years ago
You wish to generate 1.00 L of a 0.0750 M NaCl solution by diluting a more concentrated solution. What volume (in mL) of a 0.275
miss Akunina [59]

Taking into account the definition of dilution, you need to use a volume of 272.72 mL of a 0.275 M NaCl solution.

<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

<h3>Initial volume</h3>

In this case, you know:

  • Ci= 0.275 M
  • Vi= ?
  • Cf= 0.0750 M
  • Vf= 1 L

Replacing in the definition of dilution:

0.275 M× Vi= 0.0750 M× 1 L

Solving:

Vi=(0.0750 M× 1 L)÷ 0.275 M

<u><em>Vi= 0.27272 L= 272.72 mL</em></u>

In summary, you need to use a volume of 272.72 mL of a 0.275 M NaCl solution.

Learn more about dilution:

brainly.com/question/6692004

brainly.com/question/16343005

brainly.com/question/24709069

#SPJ1

8 0
2 years ago
A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de
jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

3 0
4 years ago
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