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3 years ago

Michael is using a number line to evaluate the expression –8 – 3.

Mathematics

2 answers:

suter [353]3 years ago

7 0

Answer:

-5

Step-by-step explanation: -5 because when you have a negitive and subtrace it turns to a positive so 8-3 is 5 then add your negitive back as -5.

Yanka [14]3 years ago

6 0

Answer:

Step-by-step explanation:

Michael is using a number line to evaluate the expression -8 - 3. After locating -8 on the number line , Michael could rewrite the expression as -8 + -3 and move 3 spaces to the left.

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3 years ago

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44 kg of onions cost $308. How much would 30 kg cost?

maks197457 [2]

Answer:

$210

Step-by-step explanation:

Cost of 44kg onions = $308

Cost of 1kg onion = $\frac{308}{44} = 7$

Cost of 30kg onions = $30 \times 7 = 210$

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2 years ago

Greeley [361]

Answer:

x2 2.75

Step-by-step explanation:

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3 years ago

Sarah has some grapes. She gathers 3 more grapes. She now has 40 grapes.

marysya [2.9K]

Sarah had 37 grapes to begin with

40-3=37

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2 years ago

The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?

Sliva [168]

Answer:

$A=15\pi\ units^2$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

$A=\pi r^{2}$

step 1

Find the Area of the 1st red circle

$r=2/2=1\ unit$ ---> the radius is half the diameter

$A_1=\pi (1)^{2}=\pi\ units^2$

step 2

Find the Area of the 2nd white circle

$r=4/2=2\ units$ ---> the radius is half the diameter

$A_2=\pi (2)^{2}=4\pi\ units^2$

step 3

Find the Area of the 3rd red circle

$r=6/2=3\ units$ ---> the radius is half the diameter

$A_3=\pi (3)^{2}=9\pi\ units^2$

step 4

Find the Area of the 4th white circle

$r=8/2=4\ units$ ---> the radius is half the diameter

$A_4=\pi (4)^{2}=16\pi\ units^2$

step 5

Find the Area of the 5th red circle

$r=10/2=5\ units$ ---> the radius is half the diameter

$A_5=\pi (5)^{2}=25\pi\ units^2$

The total red area is given by

$A=A_5-A_4+A_3-A_2+A_1$

substitute

$A=25\pi-16\pi+9\pi-4\pi+\pi$

$A=15\pi\ units^2$

7 0

3 years ago