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skelet666 [1.2K]
3 years ago
6

Michael is using a number line to evaluate the expression –8 – 3.

Mathematics
2 answers:
suter [353]3 years ago
7 0

Answer:

-5

Step-by-step explanation: -5 because when you have a negitive and subtrace it turns to a positive so 8-3 is 5 then add your negitive back as -5.

Yanka [14]3 years ago
6 0

Answer:

Step-by-step explanation:

Michael is using a number line to evaluate the expression -8 - 3. After locating -8 on the number line , Michael could rewrite the expression as -8 + -3 and move 3 spaces to the left.

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Is (-3,0)a solution to the equation 2x+6y=-6?
sineoko [7]

Answer:

Yes

Step-by-step explanation:

 x , y

(-3 , 0)

plug in the numbers

2(-3) + 6(0) = -6    

-6 = -6

4 0
3 years ago
A rectangle has a width of 4 inches and a length of 6 inches. A similar rectangle has a width ​
qaws [65]

Answer:

Step-by-step explanation:

6 times 4 is 24 so the answer is 24

3 0
4 years ago
Write the equation in point slope intercept form of the line that passes through (6,-11) and is parallel to the graph of y=-2/3x
Alina [70]

Answer:

y+11=-2/3(x-6)

Step-by-step explanation:

To find the parallel line, we would just plug in the numbers in the point-slope form from what we're given. We have y=-2/3x+12 and (6,-11).

Point-slope form:

y-y1=m(x-x1) → y+11=-2/3(x-6)

m represents the slope, which is -2/3 in this situation.

y1 represents the y coordinate, which is -11 in this situation. However, when we plug in negative numbers in a point-slope form, we would do the opposite of the negative number, which is to make it a positive in point-slope form.

x1 represents the x coordinate, which is 6 in this situation.

8 0
3 years ago
A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t
Sati [7]

Answer:

\frac{2}{7}

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = \frac{1}{7}

Remaining fuel after driving around the city = 1 - \frac{1}{7}

                                                                         =    \frac{7 - 1}{7}  = \frac{6}{7}

According to question:

As from the rest of the gas in the car that is \frac{6}{7}, the car can complete 3 trip to Ottawa  which means,

By unitary method:

The car can complete 3 trip by using = \frac{6}{7} tank of gas.

The car can complete 1 trip by using =  \frac{6}{7} \div 3

                                                             =\frac{6}{7} \times\frac{1}{3}

                                                             =  \frac{6}{21}

                                                             = \frac{2}{7} tank of gas

Thus, \frac{2}{7} tank of gas used for each complete trip to Ottawa.

5 0
3 years ago
Find f(-1) if f(x) = -2x^2 -x
kykrilka [37]

I hope it was helpful to you

if u like follow me

3 0
3 years ago
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