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Answer:
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Step-by-step explanation:
<em>Given: Side lengths of a right triangle 3,4 and 5 units. </em>
<em> To draw: A right triangle with the given side length. </em>
<em> Solution: </em>
<em> We know, in a right angle triangle hypotenuse is the longest side and satisfying Pythagoras theorem. </em>
<em> From the given side length, </em>
<em> Hypotenuse = 5 unit </em>
<em> We can take any of the base and perpendicular. </em>
<em> Let, Base = 3 unit </em>
<em> Perpendicular = 4 unit. </em>
<em> It a right-angle triangle with a hypotenuse 5 unit. </em>
<em> Now we draw a right angle triangle taking in the first 3 base and 4 perpendicular and second 3 perpendicular and 4 bases.</em>
The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
which simplifies to
which is 
So that is the length of both MN and LM. So far our perimeter is
Now let's use the same formula to find out the length of one of the longer segments:
which simplifies down to
which is of course
Since we have 2 of those lengths,
So our perimeter is, in the end,
That's the third choice down
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
which simplifies to
So that is the length of both MN and LM. So far our perimeter is
Now let's use the same formula to find out the length of one of the longer segments:
which simplifies down to
which is of course
Since we have 2 of those lengths,
So our perimeter is, in the end,
That's the third choice down