$\frac{t}{t-4}= \frac{t+4}{6} \\ t \neq 4 \\ 6t= (t+4)(t-4) \\ 6t=t^2-16 \\ t^2-6t-16=0 \\ D=b^2-4ac=(-6)^2-4*1*(-16)=36+64=100 \\ t_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ t_1= \frac{6-10}{2}=-2 \\ \ t_2= \frac{6+10}{2}=8$

Answer: t=-2, t=8

4 0

3 years ago

Use Euler's formula to find the missing number<br> vertices: 16<br> edges: 43<br> face:???

mrs_skeptik [129]

Answer:

The number of faces is 29

Step-by-step explanation:

we know that

The Euler's formula state that, the number of vertices, minus the number of edges, plus the number of faces, is equal to two

$V- E + F = 2$

In this problem we have

$V=16$

$E=43$

Substitute in the formula and solve for F

$16- 43 + F = 2$

$-27 + F = 2$

$F = 2+27$

$F = 29$

6 0

3 years ago