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3 years ago

Solve for x. (X+10)(x+10)=0

Mathematics

3 answers:

atroni [7]3 years ago

7 0

Answer:

use foil method-first inside outside last

Step-by-step explanation:

Mandarinka [93]3 years ago

4 0

Answer:

X = -10

Step-by-step explanation:

Adding negative ten and ten results in zero, and zero multiplied by anything is, of course, still zero.

(-10 + 10) * (-10 + 10) = 0

0 * 0 = 0

MrRa [10]3 years ago

3 0

X=-10

Because (x+10)(x+10)=0

So it becomes (x+10)^2=0

And therefore x=-10

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In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let p = proportion of young people who had earned a high school diploma.

A sample of n = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - α)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of z for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

H₀: The percentage of young people who earn high school diplomas has not increased, i.e. p = 0.80.

Hₐ: The percentage of young people who earn high school diplomas has not increased, i.e. p > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of p, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

8 0

3 years ago

Solve for the variable a D =a+b-c/3

yuradex [85]

Hey there,
solving for a is just like you think of all other letter as a constant
i.e the only variable is a
so you need to subtract b as a start
d=a+b-c/3
-b -b
=============

-b+d=a-c/3 now it's time to add c/3 (isolate a by itself in one side)

-b+d=a-c/3
+c/3 +c/3
==============
c/3-b+d=a

Hence you have solved for a

4 0

3 years ago

LAST ONE THANKSSSS

pishuonlain [190]

Answer: A

Step-by-step explanation: with my calculation, and the information you have give i have to say it is A.

6 0

2 years ago

Read 2 more answers

Greg bought a new car for £18000.

Whitepunk [10]

Answer:

£9318.96

Step-by-step explanation:

18000×0.7×0.86^(2)=£9318.96

3 0

3 years ago

Dmitry_Shevchenko [17]

Answer :-  option 3rd !!

Step-by-step explanation:

∆FGE ~ ∆ JKL

i.e, Angle FGE = angle JKL = 63°

and angle GEF = angle KLJ = 29°

also, angle GFE = angle KJL = 88°

so, the ∆FGE ~ ∆ JKL by AA property of similarity !!

• not other options because if we take corresponding angle they are not equal

For eg. for ∆ EFG ~ ∆ JKL

the angle EFG must be equal to angle JKL to be similar !!

but they are not equal !!

so, they are not similar !!

and such ,all other options except 3rd is wrong !!

7 0

3 years ago

Read 2 more answers