All categories

3 years ago

Please help me with this

Mathematics

2 answers:

Art [367]3 years ago

6 0

Answer:

the mean is 5

Step-by-step explanation:

because if you add all the numbers and divide by the number of digits you should get the equation 40/8= 5 and that´s the answer

katrin2010 [14]3 years ago

4 0

Answer: 5

Step-by-step explanation:

add up all the numbers, then divide by how many integers there are.

2+3+4+4+4+5+8+10=40

40 divided by 8 equals 5

You might be interested in

Greg plowed for 2.5 hours in the morning, 1 hour and 15 minutes in the afternoon, and 1 hour and 30 minutes in the evening. How

HACTEHA [7]

Answer:

Five hours and fifteen minutes.

Step-by-step explanation:

You add all these together and it gets five hours and fifteen minutes.

6 0

3 years ago

Can somebody please help me were learning something new but I don't get it.. :( 80 points just please help me :(

puteri [66]

$\sqrt[0.6]{534} \\ = {534}^{ \frac{1}{0.6} } \\ = 35148.1$

6 0

3 years ago

Read 2 more answers

PLEASE GUYS HELP ME :D

Debora [2.8K]

The answer is 24 because you have to do 6x4=24

7 0

3 years ago

Carlitos purchased $13.90 of roasted almonds to make his own almond milk.He purchased 5 pounds of almonds.Assuming the cost per

AleksAgata [21]

$2.78
Explanation: 13.90/5=2.78

7 0

3 years ago

PLEASE HELP!!!!!!!!!!!!! DUE SOON

Sergio039 [100]

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t$

now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)$

$\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)$

6 0

3 years ago

Please help me with this​

Please help me with this