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Wittaler [7]
3 years ago
5

Convert units (metrics) Convert 5,283 meters to kilometers. kilometers Reference sheet

Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Answer:

5.283 kilometers

Step-by-step explanation:

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The product of 25 and the number of apples
GREYUIT [131]
"Product" means multiplication
Number of apples we will use the variable "a"

ANSWER: 25a
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For exercise, mr.harris walked 1 and 3 fourths miles 5 times last week.how many miles did he walk in all?
RUDIKE [14]
Well, if he walked one and three fourths miles five times, all you have to do is multiply one and three fourths and five to get your answer.

1 \frac{3}{4}*5 \\  \\  \frac{7}{4}* \frac{5}{1}    \\  \\  \frac{7*5}{4*1}  \\  \\  \frac{35}{4} =8 \frac{3}{4}
4 0
4 years ago
Read 2 more answers
Help please ITS OF TRIGONOMETRY<br>PROVE ​
Flauer [41]

Answer:

The equation is true.

Step-by-step explanation:

In order to solve this problem, one must envision a right triangle. A diagram used to represent the imagined right triangle is included at the bottom of this explanation.  Please note that each side is named with respect to the angle is it across from.

Right angle trigonometry is composed of a sequence of ratios that relate the sides and angles of a right triangle. These ratios are as follows,

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

One is given the following equation,

\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0

As per the attached reference image, one can state the following, using the right angle trigonometric ratios,

sin(A)=\frac{a}{c}\\\\sin(B)=\frac{b}{c}\\\\cos(A)=\frac{b}{c}\\\\cos(B)=\frac{a}{c}

Substitute these values into the given equation. Then simplify the equation to prove the idenity,

\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0

\frac{\frac{a}{c}+\frac{b}{c}}{\frac{b}{c}+\frac{a}{c}}+\frac{\frac{b}{c}-\frac{a}{c}}{\frac{a}{c}-\frac{b}{c}}=0

\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}

Remember, any number over itself equals one, this holds true even for fractions with fractions in the numerator (value on top of the fraction bar) and denominator (value under the fraction bar).

\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}

\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{-(a-b)}{c}}{\frac{a-b}{c}}

1+(-1)=0

1-1=0

0=0

7 0
3 years ago
Can anyone help me ASAP please
Dmitry_Shevchenko [17]
Are you Muslim by any chance?
8 0
3 years ago
Part A
atroni [7]

Answer:

  0, 2 . . . . . (any pair of consecutive even integers)

Step-by-step explanation:

You want a pair of consecutive even integers such that twice the lesser is 4 less than two times the greater.

<h3>Setup</h3>

Let x represent the lesser of the two even integers. Then the greater is (x+2) and the given relation is ...

  2x = 2(x+2) -4

<h3>Solution</h3>

Simplifying gives ...

  2x = 2x +4 -4

  2x = 2x . . . . . . . true for any even integer x

Any pair of consecutive even integers will satisfy the relation.

  one such pair is 0, 2

     <em>check</em>: 2(2) -4 = 2(0)

5 0
2 years ago
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