Answer is D breaking apart I to not more than two
Hello!
First, we can assume the density of water to be
1 g/mL, so the volume of water would be
725 mL. The density of Acetic Acid (Pure) is
1,05 g/mL so 8 grams would represent
7,61 mLNow we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:
![[CH_3CO_2H]=\frac{8 g_{CH_3CO_2H} }{725 mL + 7,61 mL}* \frac{1000 mL}{1 L}* \frac{1 mol_{CH_3CO_2H} }{60,05 g_{CH_3CO_2H} }](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D%5Cfrac%7B8%20g_%7BCH_3CO_2H%7D%20%20%7D%7B725%20mL%20%2B%207%2C61%20mL%7D%2A%20%5Cfrac%7B1000%20mL%7D%7B1%20L%7D%2A%20%5Cfrac%7B1%20mol_%7BCH_3CO_2H%7D%20%7D%7B60%2C05%20g_%7BCH_3CO_2H%7D%20%7D)
![[CH_3CO_2H]=0,1818 M](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D0%2C1818%20M)
So, the concentration of acetic acid would be
0,1818 MHave a nice day!
Answer: The conc. of products shall increase to nullify the effect of change in concentration. For this purpose, equilibrium would shift to right.
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Reason:
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According to Le Chatelier's principle: "If a chemical system at equilibrium experiences a change in concentration, temperature, volume, or partial pressure, then the equilibrium shifts to counteract the imposed change and a new equilibrium is established."
<span>So, more reactant (weak acid or weak base) would result in shift of equilibrium towards right (i.e. toward products). Hence, the conc. of products would increase so that new equilibrium could be established.</span>
The answer you are looking for is the second option, "<span>Matter can be divided into two groups: pure substances and mixtures."
A pure substance can describe a pure element or chemically bonded elements. A pure substance cannot be broken down into further substances. An example of these would be Fe (iron) or O2 (oxygen).
A mixture is a structure made from physically combining different non-bonded substances. An example of a mixture is blood.
Both pure substances and mixtures are types of matter.</span>
Answer:
3 hydrogen bonds.
Explanation:
This is because the urea molecule has an oxygen atom bound with double bonds to the central carbon atom, and this oxygen can form a hydrogen bond with water, as well as both terminal amine groups that can also form a hydrogen bond each because of the lone pair of electrons on the nitrogen group.
