We now that 6.022x10^23 atoms are in one mole, therefore:
![56.87mol\text{ }AgNO_3\times\frac{6.022\times10^{23}mol}{1mol\text{ }AgNO_3}=3.425\times10^{25\text{ }}molAgNO_3](https://tex.z-dn.net/?f=56.87mol%5Ctext%7B%20%7DAgNO_3%5Ctimes%5Cfrac%7B6.022%5Ctimes10%5E%7B23%7Dmol%7D%7B1mol%5Ctext%7B%20%7DAgNO_3%7D%3D3.425%5Ctimes10%5E%7B25%5Ctext%7B%20%7D%7DmolAgNO_3)
Answer: 3.425x10^35 mol AgNO3
Answer:
I DO NOT UNDERSTAND THE QUESTION, BUT THANKS FOR THE COINS/TOKENS!
Explanation:
Answer:
A beta particle
Explanation:
The radioactive particle must undergo a beta decay to have the mass number unchanged but the atomic number to have decreased by one.
This type of beta decay results in the emission of a positron which is a type of beta particle. It resembles an electron but it has a positive charge of 1.
Answer:
The correct answer is option C.
Explanation:
![R=\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=R%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
r = resultant vector
y = vertical component of vector
x = horizontal component of vector
We have :
The vertical component of a vector is 40 N and its horizontal component is 25 N.
x = 25 N
y = 40 N
![R=\sqrt{(25 N)^2+(40 N)^2}](https://tex.z-dn.net/?f=R%3D%5Csqrt%7B%2825%20N%29%5E2%2B%2840%20N%29%5E2%7D)
![R = 47.17 N \approx 47.2 N](https://tex.z-dn.net/?f=R%20%3D%2047.17%20N%20%5Capprox%2047.2%20N)
47.2 N is the magnitude of the vector.
Answer:
Halogens have 7 valence electrons.
Explanation:
They are the most active non-metals including fluorine, chlorine, bromine, iodine, and astatine