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Arturiano [62]
3 years ago
12

A gas mixture consists of 60.0% Ar, 30.0% Ne, and 10.0% Kr by volume. If the pressure of this gas mixture is 80.0 kPa, what is t

he partial pressure of each of the gases
Chemistry
1 answer:
Nat2105 [25]3 years ago
4 0

Answer: The partial pressure of Argon , Neon and krypton are 48 kPa , 24 kPa and 8 kPa respectively.

Explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

p_A=x_A\times P_{total}

where, p_A = partial pressure of component A

x_A = mole fraction of A

P_{total} = total pressure

mole fraction of Ar = \frac{\text {Moles of Ar}}{\text {total moles}}=\frac{60.0}{60.0+30.0+10.0}=0.6

p_{Ar}=0.60\times 80.0kPa=48kPa

mole fraction of Ne = \frac{\text {Moles of Ne}}{\text {total moles}}=\frac{30.0}{60.0+30.0+10.0}=0.30

p_{Ne}=0.30\times 80.0kPa=24kPa

mole fraction of Kr = \frac{\text {Moles of Kr}}{\text {total moles}}=\frac{10.0}{60.0+30.0+10.0}=0.10

p_{Kr}=0.10\times 80.0kPa=8kPa

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