Question

A gas mixture consists of 60.0% Ar, 30.0% Ne, and 10.0% Kr by volume. If the pressure of this gas mixture is 80.0 kPa, what is the partial pressure of each of the gases

Answer 1

Answer: The partial pressure of Argon , Neon and krypton are 48 kPa , 24 kPa and 8 kPa respectively.

Explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

$p_A=x_A\times P_{total}$

where, $p_A$ = partial pressure of component A

$x_A$ = mole fraction of A

$P_{total}$ = total pressure

mole fraction of Ar = $\frac{\text {Moles of Ar}}{\text {total moles}}=\frac{60.0}{60.0+30.0+10.0}=0.6$

$p_{Ar}=0.60\times 80.0kPa=48kPa$

mole fraction of Ne = $\frac{\text {Moles of Ne}}{\text {total moles}}=\frac{30.0}{60.0+30.0+10.0}=0.30$

$p_{Ne}=0.30\times 80.0kPa=24kPa$

mole fraction of Kr = $\frac{\text {Moles of Kr}}{\text {total moles}}=\frac{10.0}{60.0+30.0+10.0}=0.10$

$p_{Kr}=0.10\times 80.0kPa=8kPa$