What are the solutions of the equation x6 – 9x3 + 8 = 0? Use u substitution to solve.

1 answer:

4 0

X6 – 9x3 + 8 = 0
let u = x^3
u^2 - 9u + 8 = 0
(u-8)(u-1) = 0
u = 1,8
back substitute
1 = x^3
8 = x^3

x = 1 , 2

You might be interested in

You have 26 video games in your collection.

goldenfox [79]

Answer:

Let y be the amount of xbox games

You have 26 video games. Some of them are for the xbox and some are for the the playstation. You have y amount of xbox games and 4 fewer games on the playstation. How many xbox games and playstation games do you have?

Could I please have BRAINLIEST.

3 0

4 years ago

Simplify: 4 1/2 ÷ 2:

denis23 [38]

Answer:

9/4 = 2 1/4

Step-by-step explanation:

3 0

3 years ago

Can a triangle be classified as both isosceles AND obtuse? Why or why not?

Keith_Richards [23]

Yes. And isosceles triangle only has to have 2 congruent sides while an obtuse triangle only needs one angle to be larger than 90 degrees. It is possible to have a triangle that fits both criteria.

8 0

3 years ago

What is -9/10 + -1/6 in fraction form

Sunny_sXe [5.5K]

The answer would be -16/15 and as a decimal it would be -1.06

6 0

3 years ago

Read 2 more answers

5) v= 2V A) Domain: { All real numbers. } Range: { All real numbers. } B) Domain: x s 2 Range: y20 C) Domain: x 20 Range: y20 D)

Eddi Din [679]

We will have the following:

*It will have a domain of x equal or greater than 0:

$x\ge0$

It will have a domain of y equal or greater than 0:

$y\ge0$

***

We have the following:

We determine the domain as follows:

Since the function is subject to a root, no negative value can be put in it, so its domain (Since x is not accompanied by any value in the root) can only "hold" values equal or greater than 0.

We determine the range as follows:

Since the function is subject to a root, it's solutions will never be negative, so its range can only hold values equal or greater than 0.

8 0

1 year ago