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3 years ago

15

If

=" g(x)=\frac{1}{x} " align="absmiddle" class="latex-formula"> and $h$ is a nonzero real number, then $\frac{g(x+h)-g(x)}{h}=$

1 answer:

Ksju [112]3 years ago

4 0

Fill in the given values and simplify.

$\dfrac{g(x+h)-g(x)}{h}=\dfrac{\dfrac{1}{x+h}-\dfrac{1}{x}}{h}\\\\=\dfrac{x-(x+h)}{h\cdot x(x+h)}\\\\=\dfrac{-1}{x(x+h)}$

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