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KengaRu [80]
4 years ago
5

A fair 6-sided die is rolled four times. What is the probability that the sequence of rolls is 6,5,2,1? Write your answer as a f

raction or a decimal, rounded to four decimal places.
Mathematics
2 answers:
Free_Kalibri [48]4 years ago
6 0

|\Omega|=6^4=1296\\|A|=1\\\\P(A)=\dfrac{1}{1296}\approx0.0008

Ulleksa [173]4 years ago
5 0

Answer:

1/1296

Step-by-step explanation:

The probability of rolling any particular number is 1/6.  So the probability of rolling a particular sequence of four numbers is:

(1/6) (1/6) (1/6) (1/6)

1/1296

≈ 0.0008

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Answer: 90% confidence interval is; ( - 0.0516, 0.3752 )

 

Step-by-step explanation:

Given the data in the question;  

n1 = 72, n2 = 17

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P2 = 10 / 17 = 0.5882

so

P_good = 0.75

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standard ERRROR will be;

SE = √[(0.75×(1-0.75)/72) + (0.5882×(1-0.5882)/17)]

SE = √( 0.002604 + 0.01424)

SE = 0.12978

given confidence interval = 90%

significance level a = (1 - 90/100) = 0.1, |Z( 0.1/2=0.05)| = 1.645   { from standard normal table}

so

93% CI is;

(0.75 - 0.5882) - 1.645×0.12978 <P_good - P_bad<  (0.75 - 0.5882) + 1.645×0.12978

⇒0.1618 - 0.2134 <P_good - P_bad<  0.1618 + 0.2134

⇒ - 0.0516  <P_good - P_bad< 0.3752

Therefore 90% confidence interval is; ( - 0.0516, 0.3752 )

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