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MAXImum [283]
4 years ago
8

F(x)=20/4+3e−0.2x

Mathematics
1 answer:
sdas [7]4 years ago
8 0

Answer:

12.6

Step-by-step explanation:

Given the function, F(x)=20/4+3e−0.2x

Where e is an exponential function,

To get f(3), we need to substitute x = 3 into the given function

F(3) = 20/4 + 3e - 0.2(3)

f(3) = 5 + 3e - 0.6

f(3) = 4.4+3e

Substituting the value of e = 2.718

f(3) = 4.4+3(2.718)

f(3) = 12.554

f(3) = 12.6 to the nearest tenth.

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Answer:

Step-by-step explanation:

P=(2,-3)

Q=(a,a²-2a-3)

\Delta y=a^2-2a-3-(-3)=a^2-2a\\\Delta x=a-2\\\\\displaystyle \lim_{a \to 2} \dfrac{a^2-2a-3-(-3)}{a-2}  \\\\=\lim_{a \to 2} \dfrac{a^2-2a}{a-2}  \\\\=\lim_{a \to 2} \dfrac{a(a-2)}{a-2}  \\\\=\lim_{a \to 2} \dfrac{a}{1}  \\\\=\lim_{a \to 2} a  \\\\=2\\

Proof:

y'=(x²-2x-3)'=2x-2

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