Answer:
Vb= 5.42 m/s
Vc= 5.33 m/s

Δ L= 0.43 mm
Explanation:
a) A to B
Initial velocity Va = 0 m/s
As we know that


Vb= 5.42 m/s
b)
C to D
Vd= 0 m/s

Vc= 5.33 m/s
c)
Here
Vb= 5.42 m/s
Vc= 5.33 m/s
We know that
Acceleration is the rate of change of velocity



d)
Now length compressed given as


Δ L= 0.43 mm
Answer:
B 23m/s
Explanation:
From the above information we get,
Initial velocity= 3m/s
Acceleration by gravity = 10 m/s2 (approx)
Time taken =2 seconds
v=u+at (First Equation Of Motion)
v= 3 + 10 × 2
v= 23 m/s
The momentum, p, of any object having mass m and the velocity v is

Let
and
be the masses of the large truck and the car respectively, and
and V_S be the velocities of the large truck and the car respectively.
So, by using equation (i),
the momentum of the large truck 
and the momentum of the small car
.
If the large truck has the same momentum as a small car, then the condition is

The equation (ii) can be rearranged as

So, the first scenario:


So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.
The other scenario:


So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.