1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valentinak56 [21]
3 years ago
12

Explain two scenarios where a large truck can have the same momentum as a small car.

Physics
1 answer:
KengaRu [80]3 years ago
5 0

The momentum, p, of any object having mass m and the velocity v is

p=mv\cdots(i)

Let M_L and M_S be the masses of the large truck and the car respectively, and V_L and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck = M_LV_L

and the momentum of the small car = M_SV_S.

If the large truck has the same momentum as a small car, then the condition is

M_LV_L=M_SV_S\cdots(ii)

The equation (ii) can be rearranged as

\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}

So, the first scenario:

\frac {M_L}{M_S}=\frac {V_S}{V_L}

\Rhghtarrow M_L:M_S=V_S:V_L

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\frac{M_L}{V_S}=\frac{M_S}{V_L}

\Rhghtarrow M_L:V_S= M_S:V_L

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

You might be interested in
A sprinter runs 200m west and 100 m east her displacement is
kykrilka [37]
100m so you will subtract 100m from 200m. and you will get your answer 200m-100m=100m
8 0
4 years ago
Read 2 more answers
The windshield of a speeding car hits a hovering insect. Consider the time interval from just before the car hits the insect to
HACTEHA [7]

Answer:

A. False

B True

C. False

D.False

E. True

F. False

G. False

H. False

I. True

Explanation:

A. False: The system being analyzed consists of the bug and the car.  These are the two bodies involved in the collision.

B. True: The system being analyzed consists of the bug and the car

C. False: The magnitudes of the change in velocity are different from the car and the bug. The velocity of the bug changes from 0 to the velocity of the car, while there is no noticeable change in the velocity of the car

D.False: There is barely any change in the momentum of the car since the mass of the bug is very small.

E. True: Since the mass of the bug is small, and was initially at rest, the magnitude of the change in monentum will be large because the new velocity will be that of the car.

F. False: The system being analyzed consists of the bug and the car. Those are the two bodies involved in the collision

G. False: The car barely changes in velocity since the mass of the bug is small.

H. False: The car barely changes in momentum because the collision does not affect its speed so much. on the other hand the momentum change of the bug is large since its mass is small.

I. True: The bug which was initially at rest will begin moving with the velovity of the speeding car, while the car barely changes in its velocity

5 0
3 years ago
A street light is on top of a 9 foot pole. Joe, who is 3 feet tall, walks away from the pole at a rate of 4 feet per second. At
Gekata [30.6K]

Answer:2 ft/s

Explanation:

Given

Length of Pole is 9 ft

Length of Joe is 3 ft

Joe walks away from Pole at the rate 4 ft/s

Let Joe is x m away from Pole so its shadow length is x'

From Similar triangle concept

\frac{x'}{x+x'}=\frac{3}{9}

3x'=x+x'

x=2x'

and it is given \frac{\mathrm{d} x}{\mathrm{d} t}=4 ft/s

Differentiating

\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} x'}{\mathrm{d} t}

4=2\times \frac{\mathrm{d} x'}{\mathrm{d} t}

\frac{\mathrm{d} x'}{\mathrm{d} t}=2 ft/s

6 0
3 years ago
Ice of mass 5 g at 0 °C melts to water at 0 °C.
amid [387]

Answer:

Q=1670J

Explanation:

Mass of ice: m=5g=0.005kg

Latent heat: lambda=3.34×10⁵J/kg

Heat received by ice: Q=m×lambda

Q=0.005×3.34×10⁵=5×334=1670J

5 0
3 years ago
A tire is filled with air at 10 ∘C to a gauge pressure of 250 kPa. Part A If the tire reaches a temperature of 45 ∘C, what fract
Alex_Xolod [135]

Answer:

The air fraction to be removed is 0.11

Given:

Initial temperature, T = 10^{\circ} = 283 K

Pressure, P = 250 kPa

Finally its temperature increases, T' = 45^{\circ} = 318 K

Solution:

Using the ideal gas equation:

PV = mRT

where

P = Pressure

V = Volume

m = no. of moles of gas

R = Rydberg's Constant

T = Temperature

Now,

Considering the eqn at constant volume and pressure, we get:

mT = m'T'

Thus

\frac{m}{m'} = \frac{T'}{T}                      (1)

Now, the fraction of the air to be removed for the maintenance of pressure at 250 kPa:

y = \frac{m - m'}{m} = 1 - \frac{m'}{m}

From eqn (1):

y = 1 - \frac{T}{T'}

y = 1 - \frac{283}{318} = 0.11

6 0
4 years ago
Other questions:
  • What pressure in units of torr is equal to 1.14 atm of pressure?
    15·1 answer
  • Consider the Earth and the Moon as a two-particle system.
    6·1 answer
  • What is the complex and non linear process of energy flow between species called
    10·2 answers
  • A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 3.62 g coins stacked over the 20.3 cm mark, th
    7·1 answer
  • 5. SEP Construct Explanations Why are
    9·1 answer
  • Suppose you are determining the velocity of a baseball by measuring the distance it travels, X, in a time T. You measure X to be
    13·1 answer
  • The X-ray source Cygnus X-1 has a mass of at least 11 solar masses and a diameter of only about one-quarter the diameter of the
    7·1 answer
  • Need a little help here, ASAP please. The subject is simple science, not physics.
    7·1 answer
  • What should you do if someone faints?
    14·1 answer
  • CAN SOMEONE DO THIS FOR ME!!!!!!!!!! PLEASEEEEEEEEEE
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!