100m so you will subtract 100m from 200m. and you will get your answer 200m-100m=100m
Answer:
A. False
B True
C. False
D.False
E. True
F. False
G. False
H. False
I. True
Explanation:
A. False: The system being analyzed consists of the bug and the car. These are the two bodies involved in the collision.
B. True: The system being analyzed consists of the bug and the car
C. False: The magnitudes of the change in velocity are different from the car and the bug. The velocity of the bug changes from 0 to the velocity of the car, while there is no noticeable change in the velocity of the car
D.False: There is barely any change in the momentum of the car since the mass of the bug is very small.
E. True: Since the mass of the bug is small, and was initially at rest, the magnitude of the change in monentum will be large because the new velocity will be that of the car.
F. False: The system being analyzed consists of the bug and the car. Those are the two bodies involved in the collision
G. False: The car barely changes in velocity since the mass of the bug is small.
H. False: The car barely changes in momentum because the collision does not affect its speed so much. on the other hand the momentum change of the bug is large since its mass is small.
I. True: The bug which was initially at rest will begin moving with the velovity of the speeding car, while the car barely changes in its velocity
Answer:2 ft/s
Explanation:
Given
Length of Pole is 9 ft
Length of Joe is 3 ft
Joe walks away from Pole at the rate 4 ft/s
Let Joe is x m away from Pole so its shadow length is x'
From Similar triangle concept

3x'=x+x'
x=2x'
and it is given 
Differentiating



Answer:
Q=1670J
Explanation:
Mass of ice: m=5g=0.005kg
Latent heat: lambda=3.34×10⁵J/kg
Heat received by ice: Q=m×lambda
Q=0.005×3.34×10⁵=5×334=1670J
Answer:
The air fraction to be removed is 0.11
Given:
Initial temperature, T =
= 283 K
Pressure, P = 250 kPa
Finally its temperature increases, T' =
= 318 K
Solution:
Using the ideal gas equation:
PV = mRT
where
P = Pressure
V = Volume
m = no. of moles of gas
R = Rydberg's Constant
T = Temperature
Now,
Considering the eqn at constant volume and pressure, we get:
mT = m'T'
Thus
(1)
Now, the fraction of the air to be removed for the maintenance of pressure at 250 kPa:

From eqn (1):

