A student attaches block A to a force sensor and pulls it across a frictionless table. The force on block A is

Suppose that an object undergoes simple harmonic motion, and its displacement has an amplitude A = 15.0 cm and a frequency f = 1

cestrela7 [59]

Answer:

Maximum speed ( v ) = 10.4 m/s (Approx)

Explanation:

Given:

Amplitude A = 15.0 cm = 0.15 m

Frequency f = 11.0 cycles/s (Hz)

Find:

Maximum speed ( v )

Computation:

Angular frequency = 2πf

Angular frequency = 2π(11)

Angular frequency = 69.14

Maximum speed ( v ) = WA

Maximum speed ( v ) = 69.14 x 0.15

Maximum speed ( v ) = 10.371

Maximum speed ( v ) = 10.4 m/s (Approx)

5 0

3 years ago

Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr

soldi70 [24.7K]

$Given:\\T=29.46y\approx 9.29\cdot 10^8s\\M_S\approx2.0\cdot 10^{30}kg\\G=6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2} \\\\Find:\\R=?\\\\Solution:\\\\F_g= G\frac{mM_s}{R^2} \\\\F_c= \frac{mv^2}{R} \\\\F_g=F_c\\\\G\frac{mM_s}{R^2}=\frac{mv^2}{R} \Rightarrow G\frac{M_s}{R^2}=\frac{v^2}{R}\\\\v=\omega r\\\\G\frac{M_s}{R^2}= \frac{\omega^2R^2}{R}\Rightarrow G\frac{M_s}{R^2}=\omega^2R \\\\\omega= \frac{2 \pi }{T} \\\\G\frac{M_s}{R^3}= \frac{4 \pi ^2}{T^2}$

$GM_ST^2=4 \pi ^2R^3\Rightarrow R= \sqrt[3]{ \frac{GM_ST^2}{4 \pi ^2} }\\\\\\R= \sqrt[3]{ \frac{6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2}\cdot2.0\cdot 10^{30}kg( 9.29\cdot 10^8s)^2}{4\cdot 3.14^2} } \approx 1.42\cdot 10^{12}m$

3 0

4 years ago

a car with a mass of 1000-liogram accerlerates from rest, and travels a distanceof 48 meters druing its first 4.0 seconds of uni

Alisiya [41]

24 m/s will be the velocity at this point .

What is velocity?

Velocity is the directional velocity of a moving object, observed from a given frame of reference and indicating the rate of change of position measured at a given time reference (eg 60 km/h northward). Velocity is a fundamental concept in kinematics, a branch of classical mechanics that describes the motion of bodies.

Velocity is a physical vector quantity. The scalar absolute value (magnitude) of velocity is called velocity, and its magnitude is a consistent derived unit measured in the SI (metric) system as meters per second (m/s or m⋅s−1). For example, "5 meters/second" is a scalar, but "5 meters/second east" is a vector. An object is said to be accelerating if its velocity, direction, or both change.

when v= u + at and v2-u2=2as , where u=0 ,t=4 , S = 48 m , manipulate the data and fine the answer.

To learn more about velocity , click the given link ; brainly.com/question/80295

#SPJ4

5 0

1 year ago

Heavier elements require higher temperatures to fuse. After stars run out of hydrogen in their cores, they leave the main sequen

Kruka [31]

Answer:

A. Add mass to the Sun.

Explanation:

A. Add mass to the Sun.

Adding mass will make to take more time for the hydrogen to run out and hence, enough temperature will be developed to fuse helium atom into other heavier elements, and eventually get hot enough to fuse the helium in their cores into carbon.

The only hypothetical solution is that we need to add Mass to the Sun.

5 0

4 years ago

A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the bob's mass is do

Alborosie

1. B. T

The period of a simple pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$ (1)

where

L is the length of the pendulum

g is the gravitational acceleration

From the formula, we notice that the period of the pendulum does not depend on the mass of the bob. Therefore, when the bob's mass is doubled, the period does not change.

2. C: sqrt(6)*T

In this case, the pendulum is brought to the moon, where the gravitational acceleration is

$g'=\frac{g}{6}$

If we substitute this value into the equation for the period (1), we find the new period of the pendulum:

$T'=2\pi \sqrt{\frac{L}{g'}}=2\pi \sqrt{\frac{L}{(g/6)}}=\sqrt{6}(2\pi \sqrt{\frac{L}{g}})=\sqrt{6} T$

3. B: It will no longer oscillate because there is no gravity in space

Explanation:

The motion (oscillation) of the pendulum is caused by the force of gravity, which "pulls" the bob towards the equilibrium position. If there is no gravity, then there is no force acting on the bob, therefore the pendulum can no longer oscillate.

So, the correct answer is

B: It will no longer oscillate because there is no gravity in space

4 0

4 years ago

Read 2 more answers