Answer:
Explanation:
A. Using
Sinစ= y/ L = 0.013/2.7= 0.00481
စ=0.28°
B.here we use
Alpha= πsinစa/lambda
= π x (0.0351)sin(0.28)/588E-9m
= 9.1*10^-2rad
C.we use
I(စ)/Im= (sin alpha/alpha) ²
So
{= (sin0.091/0.091)²
= 3*10^-4
During the daytime, I have mostly line symmetry.
During the night, I often have almost spherical symmetry.
Answer:
m = 5.22 kg
Explanation:
The force acting on the bucket is 52.2 N.
We need to find the mass of the bucket.
The force acting on the bucket is given by :
F = mg
g is acceleration due to gravity
m is mass
![m=\dfrac{F}{g}\\\\m=\dfrac{52.2}{10}\\\\=5.22\ kg](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7BF%7D%7Bg%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7B52.2%7D%7B10%7D%5C%5C%5C%5C%3D5.22%5C%20kg)
So, the mass of the bucket is 5.22 kg.
Answer:
Explanation:
Given,
initial angular speed, ω = 3,700 rev/min
=
final angular speed = 0 rad/s
Number of time it rotates= 46 times
angular displacement, θ = 2π x 46 = 92 π
Angular acceleration
![\alpha = \dfrac{\omega_f^2 - \omega^2}{2\theta}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cdfrac%7B%5Comega_f%5E2%20-%20%5Comega%5E2%7D%7B2%5Ctheta%7D)
![\alpha = \dfrac{0 - 387.27^2}{2\times 92\ pi}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cdfrac%7B0%20-%20387.27%5E2%7D%7B2%5Ctimes%2092%5C%20pi%7D)
![\alpha = -259.28 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%20-259.28%20rad%2Fs%5E2)