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vampirchik [111]
3 years ago
8

A 10 kg bowling ball sits at the top of a 10 m hill and then slides down its icy hillside.

Physics
2 answers:
Nataly_w [17]3 years ago
5 0
We need more informtion
andriy [413]3 years ago
4 0
So is there an answer choice if not the answer would be 100m
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In a parallel circuit, if bulb #2 were to blow out, bulb #1 would stay lit or go out?
valkas [14]
Vhychhguuhkxkgxjgzkg
8 0
3 years ago
What amount of heat is required to raise the temperature of 25 grams of copper to cause a 15ºC change? The specific heat of copp
Lina20 [59]

The amount of heat required is B) 150 J

Explanation:

The amount of heat energy required to increase the temperature of a substance is given by the equation:

Q=mC\Delta T

where:

m is the mass of the substance

C is the specific heat capacity of the substance

\Delta T is the change in temperature of the substance

For the sample of copper in this problem, we have:

m = 25 g (mass)

C = 0.39 J/gºC (specific heat capacity of copper)

\Delta T = 15^{\circ}C (change in temperature)

Substituting, we find:

Q=(25)(0.39)(15)=146 J

So, the closest answer is B) 150 J.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

3 0
3 years ago
If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, what happens to the volume of the g
oee [108]

Answer:

Explanation:

According to Boyle's law  for constant temperature of gas Pressure is inversely proportional to the volume of gas.

PV=nRT

PV=constant

P\propto \frac{1}{V}

if Pressure is tripled then

P\times V_1=3P\times V_2

V_2=\frac{V_1}{3}

Volume becomes one-third of original volume          

7 0
3 years ago
The work energy principle states that the change in kinetic energy of an object is equal to the net work done on the object. If
sattari [20]

Answer:

v=\sqrt{2gh}\ m/s

Explanation:

From work energy theorem

Work done by all forces = Change in kinetic energy

Lets take

m= mass of object

h=height from the ground surface

initial velocity of object = 0 m/s

The final velocity of object is v

Work done by gravitational force = m g . h

The final kinetic energy = 1/2 m v²

So

Work done by all forces = Change in kinetic energy

m g h =  1/2 m v² - 0

v² = 2 g h

v=\sqrt{2gh}\ m/s

6 0
3 years ago
A package is dropped from a helicopter moving upward at 15m/s. If it takes 10 s before the package strikes the ground, how high
Vlad1618 [11]

Answer:

A package is dropped from a helicopter moving upward at 15 m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released? (Disregard air resistance.)

Show step by step please.

Note: The answer is given it's should be 1000 m ??

This what i can up with so see what it is kid

Explanation:

6 0
3 years ago
Read 2 more answers
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