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vampirchik [111]
3 years ago
8

A 10 kg bowling ball sits at the top of a 10 m hill and then slides down its icy hillside.

Physics
2 answers:
Nataly_w [17]3 years ago
5 0
We need more informtion
andriy [413]3 years ago
4 0
So is there an answer choice if not the answer would be 100m
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A robin flies a distance of 45963 cm. How far has it flown in kilometers?
alina1380 [7]

Answer:

0.46km

Explanation:

45963cm/100cm=459.63m/1000m=0.45963 or 0.46km

6 0
3 years ago
A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the
lisabon 2012 [21]

Magnitude of acceleration = (change in speed) / (time for the change) .

Change in speed = (ending speed) - (starting speed)

                            =       zero            - (43 m/s)

                            =          -43 m/s .

Magnitude of acceleration = (-43 m/sec) / (0.28 sec)

                                          =  (-43 / 0.28)  (m/sec) / sec

                                          =        153.57...  m/s²

                                          =        1.5...  x 10²  m/s²  .

5 0
3 years ago
Read 2 more answers
The metal wire in an incandescent lightbulb glows when the lights is switch on and stops glowing when switched off. This simple
lutik1710 [3]

Answer:

When the metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off, this is an example of resistance, which provides light and heat.  

Explanation:

4 0
3 years ago
Read 2 more answers
Cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, ini
kakasveta [241]

The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s

<h3>Conservation of Linear Momentum</h3>

Given Data

  • Mass of cart one M1  = 150kg
  • Initial Velocity U1 = 8m/s
  • Final VelocityV1 = 5 m/s

Mass of cart two M2  = 150kg

Velocity U2 = 6m/s

Applying the principle of conservation of linear momentum we have

M1U1+M2U2 = M1V1+ M2V2

a. what is the speed of cart b after collision

substituting our given data we have

150*8+ 150*6 = 150*5+150*V2

1200 + 900 = 1200+ 150V2

2100 - 1200 = 150V2

900 = 150V2

Divide both sides by 150

V2 = 900/150

V2 = 6m/s

b. what is the total momentum of the system before and after collision

Total Momentum in the system is

Total momentum = Momentum before Impact+ Momentum after Impact

Total momentum = M1U1+M2U2 + M1V1+ M2V2

Total momentum = 1200 + 900 + 1200+ 900

Total momentum = 4200 kg m/s

Learn more about Conservation of Linear Momentum here:

brainly.com/question/7538238

6 0
2 years ago
At the race track, one race car starts its engine with a resulting intensity level of 104.0 dB at point P. Then 6 more cars star
dem82 [27]

To solve the problem it is necessary to apply the concepts related to sound intensity. The most common approach to sound intensity measurement is to use the decibel scale:

\beta (dB) = 10log_{10}(\frac{I}{I_0})

Where,

I_0 = 1*10^{-12} is a reference intensity. It is the lowest or threshold intensity of sound a person with normal hearing can perceive at a frequency of 1000 Hz.

I = Sound intensity

Our values are given by,

\beta = 104dB

\#Autos = 7

For each auto the intensity would be,

104 = 10log\frac{I}{1*10^{-12}}

10.4= log_{10} (\frac{I}{10^{-12}})

10^{10.4}*10^{-12}=I

I = 0.02511W/m^2

Therefore the sound intesity for the 7 autos is

I= 7* 0.02511

I = 0.1748W/m^2

The sound level for the 7 cars in dB is

\beta (dB) = 10log_{10}(\frac{0.1748}{1*10^{-12}})

\beta (dB) = 112.42dB

8 0
3 years ago
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