Question

Write the equation of the line with a slope of 1/6 that contains (12,-7)

Answer 1

$\bf (\stackrel{x_1}{12}~,~\stackrel{y_1}{-7})~\hspace{10em} slope = m\implies \cfrac{1}{6} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-7)=\cfrac{1}{6}(x-12) \\\\\\ y+7=\cfrac{1}{6}x-2\implies y=\cfrac{1}{6}x-9$

Answer 2

Hello there,

Slope intercept form:                                 y = mx + b

Slope:                                                              1/6

Point: (12,-7)

Plug in and Solve:

-7 = 1/6(12) + b

-7 = 2 + b

-2    -2

—————-

-9 = b

Answer: y = 1/6x - 9

Hope I helped!

-Char