1. 5 3/4+("-" 1/4) 2. "-" 2/3+1/63. "-" 8/5+("-" 3/4)
1 answer:
You might be interested in
Answer:
Point-slope equation of this line:
.
Step-by-step explanation:
The equation for a line in a cartesian plane can take multiple forms. This question gives
- a point on the line, and
- the slope of the line.
The point-slope form will the most appropriate.
What is the point-slope form equation of a line ?
In general,
,
where
is the x-coordinate of the given point on the line,
is the y-coordinate of the given point on the line, and
is the slope or gradient of the line.
In other words, the point on the line.
For this line,
- The point is
, where
and
.
- Gradient of the line
.
Thus the equation for this line:
.
The linear approximation to 
centered at 
is
What this means is that you can use the tangent line to at to get a decent approximation of at some other value of 
to within a certain degree of accuracy depending on how close this value is close to 
. (Note that when , the approximation is exact; 
.)
So what you're asked to do is find an approximate value of a zero of near 
. That is to say, you're looking for some value 
such that 
, but all you have at your disposal is the linear approximation to the function.
You know that if is a zero of 
, then , so you get
Solving for, you find
This means that an approximate zero of is 
.
What this means is that you can use the tangent line to
So what you're asked to do is find an approximate value of a zero of
You know that if
Solving for
This means that an approximate zero of