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Lerok [7]
3 years ago
9

1. 5 3/4+("-" 1/4) 2. "-" 2/3+1/63. "-" 8/5+("-" 3/4)

Mathematics
1 answer:
gregori [183]3 years ago
4 0

Answer:

<h2>BELOW</h2>

Step-by-step explanation:

1.

5\frac{3}{4} +(-\frac{1}{4} )\\\\5\frac{3}{4}=\frac{5\times4+3}{4}=\frac{23}{4}\\\\\frac{23}{4} +(-\frac{1}{4} )\\\\=\frac{23}{4}-\frac{1}{4}\\\\=\frac{23-1}{4}\\\\=\frac{22}{4}\\\\=5\frac{1}{2}

2.

-\frac{2}{3} +\frac{1}{6} \\\\L.C.M \:OF\:3,6\: =6\\\\Adjust\:fractions\:based \:on \:their\:L.C.M\\\\=-\frac{4}{6}+\frac{1}{6}\\\\=-\frac{4}{6}+\frac{1}{6}\\\\=\frac{-3}{6}\\\\=-\frac{3}{6}\\\\=-\frac{1}{2}

3.

-\frac{8}{5} +(-\frac{3}{4} )\\\\L.C.M \:OF\:5,4\: =20\\\\Adjust\:fractions\:based \:on \:their\:L.C.M\\\\=-\frac{32}{20}-\frac{15}{20}\\\\=\frac{-32-15}{20}\\\\=\frac{-47}{20}\\\\=-\frac{47}{20}\\\\=-2\frac{7}{20}

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Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
4 years ago
Please do 1-10 no work needed
notka56 [123]

Answer(s):

1: -6

2: 31/3=10.3(with repeat)=10 1/3

3: 0

4: 21/4=5.25=5 1/4

5: -4

6: 6

7: 3

8: 2

9: -13

10: -7

Hope I helped! :)

7 0
3 years ago
Sphere and a cylinder have the same radius and height. The volume of the cylinder is 64 meters cubed.
Mrrafil [7]

Answer:

C. 128/3 meters cubed

Step-by-step explanation:

The volume of a cylinder is denoted by: V=\pi r^2h, where r is the radius and h is the height. We know it's equal to 64, so we can set that equal to V:

V=\pi r^2h

64=\pi r^2h

We know that the sphere and cylinder have the same height and radius. However, the "height" of a sphere is actually the same as its diameter, which is twice its radius. Then, we can replace h in the above equation with 2r:

64=\pi r^2h

64=\pi r^2*2r=2\pi r^3

\pi r^3=64/2=32

Now, the volume of a sphere is denoted by: V=\frac{4}{3} \pi r^3, where r is the radius. From above, we know that \pi r^3=32, so we can plug this into the equation:

V=\frac{4}{3} \pi r^3

V=\frac{4}{3} *32=128/3

Thus, the answer is C.

4 0
3 years ago
Read 2 more answers
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Vilka [71]

Answer:

1<x<4

Step-by-step explanation:

this helps me out a lot in my math class

5 0
3 years ago
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In-s [12.5K]

Answer:

-5/9

Step-by-step explanation:

Note. If the line is parallel, then the slope is shared. If the line is perpendicular (directly opposite), it means to flip the sign as well as the fraction.

The slope of line g is 9/5. This means that the slope of line h, (which is perpendicular to line g), would be the opposite, or -5/9

-5/9 is your answer.

~

6 0
3 years ago
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