3 should be added to the tiles
Answer:
10.31 pounds
Step-by-step explanation:
First, we multiply 1.3 x 2 because he is gaining 1.3 for the next TWO weeks.
1.3 x 2 = 2.6
Now, add 7.71 + 2.6 because that is the weight he started with.
7.71 + 2.6 = 10.31
Her brother will weight 10.31 pounds if he is 7.71 lbs and continues to gain 1.3 pounds each week for two weeks.
Answer:
D: -5(-6x^2 + x + 2)
E: 5(2x + 1)(3x − 2)
Step-by-step explanation:
The <em>first two answer choices have incorrect constants</em> (25 and 3 vs -10). A factor of 5 is removed from the remaining answer choices, so let's remove a factor of 5 and see what we get:
30x^2 -5x -10 = 5(6x^2 -x -2)
An additional x cannot be factored from the expression, so <em>choice C can be eliminated</em>.
Multiplying each of these factors by -1 will make the product correspond to answer choice D.
Factoring will make it correspond to answer choice E, best verified by finding the x-term of the product of the binomial factors:
E: 2x(-2) +1(3x) = -x, as required
F: 2x(2) -1(3x) = x, wrong sign
The equivalent expressions are those of choices D and E.
Team A) 45 people
Team B) 55 people
A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A.
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
</span>or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20
As you can, we get the same answer for both.
B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
or 5.79 x 10^22
Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
